HELP HELP PLS !! 5N 21N
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The question has missing information.
The options are given below.
a.The equilibrium lies far to the right
b. The reaction will proceed very slowly
c. The reaction contains significant amounts of products and reactants at equilibrium.
d. The equilibrium lies far to the left
Answer : The correct answer is option c: The reaction contains significant amounts of products and reactants at equilibrium.
Explanation :
Option a is not correct because for equilibrium to lie far to the right, we need a large value of keq ( Keq >>> 1 ), but the keq value is small.
option b is also not correct because in order to predict the speed of the reaction, we need more information. The speed of the reaction cannot be predicted using Keq value.
Option d is not correct because for Keq to lie far to the left, it has to be very very small. ( Keq <<< 1)
The value of equilibrium constant is given as 4.24. This value is very near to 1.
Equilibrium constant for this reaction is calculated as
When Keq = 1,
That means concentrations of products and reactants are equal.
Since the keq value for our reaction is very close to 1, we can say that , there are significant amounts of reactants and products at equilibrium.
Therefore option C is the correct option.
Answer : Given data ;
Δ G° = 212 KJ/molTemperature is = 25+273 = 298 KAnd gas constant R = 0.008314 KJ/mol
The reaction is NiO(s) ⇌ Ni(s) +
We can find out the pressure on oxygen by using the equation of gibb's free energy with remainder quotient which is, ΔG = ΔG° +RT lnQ
when at equilibrium Q = K, here K is equilibrim constant, and ΔG becomes 0;
so we get, 0 = ΔG° + RT ln K
on rearranging we get, ln K = ΔG° / (RT)
ln K = 212 / (0.00831 X 298) = 85.6
Here, now K = = 1.51 X
When we get K = 1.51 X
But, K =
So, (1.51 X ) 
= 3.87 X 
Hence, the pressure of oxygen will be = 3.87 X Pa
Now, Pa to atm conversion will be 3.756 X
atm
Δ G° = 212 KJ/molTemperature is = 25+273 = 298 KAnd gas constant R = 0.008314 KJ/mol
The reaction is NiO(s) ⇌ Ni(s) +
when at equilibrium Q = K, here K is equilibrim constant, and ΔG becomes 0;
so we get, 0 = ΔG° + RT ln K
on rearranging we get, ln K = ΔG° / (RT)
ln K = 212 / (0.00831 X 298) = 85.6
Here, now K = = 1.51 X
When we get K = 1.51 X
But, K =
Hence, the pressure of oxygen will be = 3.87 X
Now, Pa to atm conversion will be 3.756 X
Answer:
Order of the cycle:
Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.
Explanation:
<u>Step -1:</u>
Carbon dioxide is taken in by plants during photosynthesis.
<u>Step -4;</u>
The animal eats a plant and uses its carbohydrates for energy.
<u>Step - 3</u>
The animal releases the carbon dioxide back into the atmosphere during respiration.
<u>Step -2</u>
The cycle repeats when the carbon stored in the atmosphere as carbon dioxide gas is taken in.
Therefore, order of the cycle is Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.
