1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bulgar [2K]
3 years ago
7

What is the bronsted in the following equation HBr+H20 H30+ +Br​

Chemistry
1 answer:
notsponge [240]3 years ago
6 0

Answer:

Explanation:HBr = Bronsted Acid

H20= Bronsted Base

Br=conjugate base

H30+=conjugate acid

Conjugate base is what is left over after an acid has donated a proton and conjugate acid is what us formed when the base receives proton

You might be interested in
What is a chemical property of mercury?
zaharov [31]
The chemical property of mercury is that it reacts with oxygen
8 0
3 years ago
Question 7
Svet_ta [14]

Answer:

Check if the ions of two compounds exchange places.

Explanation:

The definition of single replacement is a reaction when an ion replaces another ion, thus the name.

7 0
3 years ago
Read 2 more answers
Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti
gayaneshka [121]

Answer : The value of K for this reaction is, 2.6\times 10^{15}

Explanation :

The given chemical reaction is:

CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)

Now we have to calculate value of (\Delta G^o).

\Delta G^o=G_f_{product}-G_f_{reactant}

\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]

where,

\Delta G^o = Gibbs free energy of reaction = ?

n = number of moles

\Delta G^0_{(HCH_3CO_2(g))} = -389.8 kJ/mol

\Delta G^0_{(CH_3OH(g))} = -161.96 kJ/mol

\Delta G^0_{(CO(g))} = -137.2 kJ/mol

Now put all the given values in this expression, we get:

\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]

\Delta G^o=-89.4kJ/mol

The relation between the equilibrium constant and standard Gibbs, free energy is:

\Delta G^o=-RT\times \ln K

where,

\Delta G^o = standard Gibbs, free energy  = -89.4 kJ/mol = -89400 J/mol

R = gas constant  = 8.314 J/L.atm

T = temperature  = 30.0^oC=273+30.0=303K

K = equilibrium constant = ?

Now put all the given values in this expression, we get:

-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K

K=2.6\times 10^{15}

Thus, the value of K for this reaction is, 2.6\times 10^{15}

4 0
4 years ago
Nitrogen - 14.0067
alina1380 [7]

Answer:

potasium to erbium

Explanation:

3 0
3 years ago
In the equation shown, what are the reactant(s)?
Vladimir [108]
C3H8 + O2 (please give me brainliest$
4 0
3 years ago
Other questions:
  • a 0.201 M aqueous solution of NaOH was used to titrate HCl in an aqueous solution. 30.5 ml of the NaOH was needed to neutralize
    7·1 answer
  • What evidence of a chemical reaction might you see in the following cases?
    12·1 answer
  • What is the volume of an object with the mass of 7.9 grams in the density of 1.28g/ml.
    15·1 answer
  • Amanda's younger brother tells her that he saw a comet with a long and bright tail move rapidly across the sky. Amanda tells him
    5·2 answers
  • 10 POINTS PLS HELP ASAP WILL MARK BRANLIEST
    9·2 answers
  • What is the molar mass of Ammonium Carbonate?
    5·1 answer
  • 4. What is the common name of the compound CaOCI,?​
    11·1 answer
  • After air enter the body through the nose or mouth it then goes to the <br> what?
    10·1 answer
  • Nuclear forces exists because the particles in the nucleus are ?
    6·1 answer
  • Fossil fuels could have formed for all these items EXCEPT-
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!