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olga_2 [115]
3 years ago
6

The decay of which radioisotope can be used to estimate the age of the fossilized remains of an insect?

Chemistry
2 answers:
exis [7]3 years ago
4 0

Answer:

C-14

Explanation:

Carbon-14 is a naturally occurring isotope of carbon.

It is present in all living organism.

When a living organism dies or fossilized, the radioactive carbon-14 undergoes disintegration.

If we can measure the amount of Carbon-14 left in a fossil we can determine the age of the dead organism.

This is known as carbon dating.

Dmitriy789 [7]3 years ago
3 0
(4) C-14 Carbon is found in all living organisms.
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As you were climbing a a mountain, you noticed that rocks were crumbling below your feet and moving down the mountain. What two
Flauer [41]

Answer:

Weathering and erosion

Explanation:

Weathering can be explained as the breaking down of rocks/minerals on the surface of the Earth as a result of contact with biological organism, water, air and other factors

. There are 3 common types of weathering which are;

1) physical weathering

2) biological weathering

3) chemical weathering

Erosion can be regarded as a geological process, whereby earthen material are been transported away by natural forces, these forces could be wind as well as water.

Therefore, as you were climbing a a mountain, you noticed that rocks were crumbling below your feet and moving down the mountain. What is observed are weathering and erosion processes.

After the weakening and broken up of the rock by weathering then erosion transport the bit of the rock down the mountain as you are climbing, which means the "weathering process" breakdown and the "erosion process" involves the transport or movement of the bit of the rocks

6 0
3 years ago
An aqueous solution of glucose has molality of 6.81 and a density of 1.2 g/ml what is the molarity of glucose in the solution
andriy [413]

Answer:

the molarity is 3.68 moles/L

Explanation:

the molality of the solution of sucrose is

m= moles of glucose / Kg of solvent (water)= 6.81 ,

since the molecular weight of glucose is 180.156 gr/mole , then per each kilogram of solvent there is

6.81 moles*180.156 gr/mole + 1000 gr of water = 2226.86 gr of solution

from the density

volume of solution = mass of solution/density = 2286.86 gr / 1.2 gr/ml = 1855.71 ml

therefore there is 1000 gr of water in 1855.71 ml

then the molarity M is

M= moles of glucose / L of solution = (moles of glucose /  Kg of solvent) *  (Kg of solvent/L of solution) = 6.81 moles/Kg * 1Kg/1.85 L = 3.68 moles/L

M= 3.68 moles/L

Note:

- Would be wrong in this case to assume density of water = 1 Kg/L since the solution is heavily concentrated in glucose and therefore the density of water deviates from its pure value.

3 0
4 years ago
Consider the following chemical equilibrium:
jok3333 [9.3K]

Answer:

Kc = [CH₄] / [H₂]²

Kp = [CH₄] / [H₂]² * (0.082*T)^-1

Explanation:

Equilibrium constant, Kc, is defined as the ratio of the concentrations of the products over the reactants. Also, each concentration of product of reactant is powered to its coefficient.

<em>Pure solids and liquids are not taken into account in an equilibrium</em>

Thus, for the reaction:

C(s)+ 2H₂(g) ⇌ CH₄(g)

Equilibrium constant is:

<h3>Kc = [CH₄] / [H₂]²</h3>

Now, using the formula:

Kp = Kc* (RT)^Δn

<em>Where R is gas constant (0.082atmL/molK), T is the temperature of the reaction and Δn is difference in coefficients of gas products - coefficients of gas reactants (1 - 2= -1)</em>

Replacing:

<h3>Kp = [CH₄] / [H₂]² * (0.082*T)^-1</h3>

<em />

4 0
3 years ago
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