Answer:
Explanation:
Find the final velocity at which it struck the ground by using the kinetic energy formula.
Now use kinematics to solve for the vertical displacement. We were given the initial velocity and acceleration can be assumed to be 9.8
Δy = 13.6 meters
Answer:
# = 6.6 10¹⁵ electrons for r = 1 m
# = 6.6 10¹³ electrons for r= 1 cm
Explanation:
The electric force is given by Coulomb's law
F = k q₁ q₂ / r²
Where k is the Coulomb constant that is worth 8.99 10⁹ N m²/C², q are the charges and r the distance between them.
Let's apply this equation to our case. Initially the spheres are not attracted so the net charge in each of them is zero, removing electrons in one of them is a positive net charge of equal value to the negative charge removed. The specific answer of this exercise depends on the distance of the two spheres, by calculation we assume that it is 1 m
The charge of an electron is q₀ = -1.6 10⁻¹⁹ C, the total charge is
q = #_electron q₀
F = k # q₀ # q₀ / r²
#² = F r² / k q₀²
# = √ F r² / k q₀²
Let's calculate for r = 1 m
# = √ [1 10⁴ 1 / 8.99 10⁹ (1.6 10⁻¹⁹)²]
# = √ [43.45 10³⁰]
# = 6.6 10¹⁵ electrons for r = 1 m
If the distance is reduced to r = 1 cm = 1 10⁻² m
The number of electrons is reduced to
# = 6.6 10¹³ electrons
Answer:
90°
Explanation:
This angle is the measured between the force applied and the displacement where the force vector and the displacement vector are on opposite direction.
The formula for work in this case is ;
W=F*d* cos ∅ where ;
F= force, d= distance and ∅ is the work angle
For minimum work ∅ = 90°
For maximum work ∅ = 0°
Explanation:
The principle of cross-cutting relationships states that a fault or intrusion is younger than the rocks that it cuts through. The fault labeled "E" cuts through all three sedimentary rock layers (A, B,and C) and also cuts through the intrusion (D). So the fault must be the youngest formation that is seen and known of.
Well, where is the table at?
If you, don't have the table then try going with D. Valley. I hope this helps :)