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Anettt [7]
3 years ago
15

A man whose salary is Ghs1624.5 per month received a Christmas bonus of 4/5 of his monthly salary in the month of December. Find

his pay for that month.
Mathematics
1 answer:
lakkis [162]3 years ago
5 0

3914 1404 393

Answer:

  Ghs 2924.1

Step-by-step explanation:

The man's pay including his bonus was ...

  (1 +4/5)(Ghs 1624.5) = Ghs 2924.1

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The table shows the relationship between the number of minutes Rodney spends practicing playing the piano p, and the number of m
vagabundo [1.1K]

<u>Answer-</u>

The equation that describes the pattern is,

\boxed{\boxed{y=2{x}+30}}

<u>Solution-</u>

P = Number of minutes Rodney spends practicing playing the piano

G = Number of minutes Rodney spends practicing playing the guitar

Taking P on x axis and G on y axis, the points are,

(0,30),(15,60),(30,90),(45,120)

Taking first two points i.e (0,30),(15,60), the line equation will be,

\Rightarrow \dfrac{y-y_1}{y_2-y_1}=\dfrac{x-x_1}{x_2-x_1}

\Rightarrow \dfrac{y-30}{60-30}=\dfrac{x-0}{15-0}

\Rightarrow \dfrac{y-30}{30}=\dfrac{x}{15}

\Rightarrow 15(y-30)=30{x}

\Rightarrow y-30=2{x}

\Rightarrow y=2{x}+30

Putting the other two points i.e (30,90),(45,120) in the equation, they also satisfy the equation. That means they are also on the same line y=2{x}+30.

From the result, it is evident that P and G are linearly related.

3 0
3 years ago
nilai rata2 matematik dari 10 siswa adalah 55 jika digabungkan lagi dengan 5 siswa maka nilai rata2 menjadi 53tentukan nilai rat
zaharov [31]
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6 0
3 years ago
What is the y-intercept of the graph of the function f(x) = x^2 + 3x + 5?
Semenov [28]

Answer:

(0,5)

Step-by-step explanation:

To find the y-intercept, substitute in 0 for x and solve for y.

y=x^2 + 3x + 5

y=(0)^2 + 3(0) +5

y=0+0+5

y=5

Since there is no x coordinate for a y-intercept, the answer is (0,5)

7 0
3 years ago
What radical expression is not simplified?
rodikova [14]
B 2/10 is not simplified because you can divide each number by 2 reducing it to 1/5.
5 0
3 years ago
I put a picture
Ksivusya [100]

Answer:

Yes, an arrow can be drawn from 10.3 so the relation is a function.

Step-by-step explanation:

Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.

The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.

In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.

However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.

3 0
3 years ago
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