9514 1404 393
Answer:
Step-by-step explanation:
If find that "substitution" works well for "mixture" problems like this. Usually, you will want to substitute for the lower-priced item, so that you're solving for the number of higher-priced items.
Let "a" and "k" stand for the number of adult and kid tickets, respectively.
a + k = 54 . . . . . . total number of tickets sold
8a +5k = 360 . . . total revenue
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To substitute for k, we solve the first equation for k:
k = 54 -a
Now, we substitute that into the second equation:
8a +5(54 -a) = 360
3a = 90 . . . . . . . . . . . subtract 270 from both sides; collect terms
a = 30 . . . . . . . . . . . . divide by 3
k = 54 -30 = 24 . . . . . use the above formula for k
The number of kids was 24; the number of adults was 30.