Answer:
5:4
Explanation:
The scale factor would be 15:12 because the sides are corresponding. This ratio simplifies to 5:4 when divided by 3.
The probability of randomly selecting an order that has at least 760
calories is 0.16
Step-by-step explanation:
The number of calories in an order of poutine at a certain fast food
restaurant is approximately normally distributed
1. The mean "μ" is 740 calories
2. The standard deviation "σ" is 20 calories
3. We need to find the probability of randomly selecting an order that
has at least 760 calories (x ≥ 760)
At first let us calculate z-score
∵ z = (x - μ)/σ
∵ x = 760 calories
∵ μ = 740 calories
∵ σ = 20 calories
∴ z =
Use the normal distribution table of z (area to the left of z-score) to
find the corresponding area to z-score of 1
∵ The area corresponding of z = 1 is 0.84134
∵ We interested in x ≥ 760, we need the area to the right of z-score
∴ P(x ≥ 760) = 1 - 0.84134
∴ P(x ≥ 760) = 0.15866 ≅ 0.16
The probability of randomly selecting an order that has at least 760
calories is 0.16
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Answer:
h(t) = –16t^2 + 46*t + 6
Step-by-step explanation:
To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.
Please see the attached image below, to find more information about the graph
The projectile formula is
h(t) = -16*t^2 + v*t + h0
Where,
v = initial vertical velocity of the ball in feet per second
h0 = initial height of the ball in feet
We need to fill the equation
h(t) = –16t^2 + v*t + 6
Where
v is the missing speed
If we go through many values of v until we find the same graph as the one showed in the first picture, we can find that
v = 46 ft/s