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Basile [38]
2 years ago
11

Mandy has a 10.2-ounce container of mustard. She uses 130 of the mustard to put on her hot dog each time. How many ounces of mus

tard are left after she has eaten 6 hot dogs?
Record your answer and fill in the bubbles on your answer document. Be sure to use the correct place value.
Mathematics
2 answers:
Marianna [84]2 years ago
7 0

Answer:

x

Step-by-step explanation:

Triss [41]2 years ago
7 0

This is from a test isnt it? Is this the snapshot i had exactly this.......CHEATER O-o

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State whether the following number is divisible by 2,5, or 10. 215
adoni [48]

Answer

215 can only be divided by 5

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C. Look for Relationships How do the processes you used for parts A and B differ? How are they the same?
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Step-by-step explanation:

Relationship is a ver beautiful friend one answer

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Between which two ordered pairs does the graph of f(x) = 1/2x2 + x – 9 cross the negative x-axis? (–6, 0) and (–5, 0) (–4, 0) an
lbvjy [14]

Answer:

Between (-6,0) and (-5,0).

Step-by-step explanation:

When it crosses the x axis, it's an x-intercept. To find the x-intercept, set y (aka f(x)) to zero. The solutions to the equation are approximately 3.36 and - 5.36. Since you're finding the negative x-intercept, you only need the negative solution - 5.36. This is in between (-6,0) and (-5,0).

3 0
3 years ago
The formula for finding the area of a circle is A=pi r 2.Solve the formula for r
olga55 [171]

Answer:

See Explanation

Step-by-step explanation:

A = \pi {r}^{2}  \\  \\  \frac{A}{\pi}  =  {r}^{2}  \\  \\ \huge \red{ \boxed{ r =  \sqrt{\frac{A}{\pi}  } }}

3 0
3 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
AURORKA [14]

Answer:

(−0.103371 ; 0.063371) ;

No ;

( -0.0463642, 0.0063642)

Step-by-step explanation:

Shift 1:

Sample size, n1 = 30

Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm

Shift 2:

Sample size, n2 = 25

Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17

Mean difference ; μ1 - μ2

Zcritical at 95% confidence interval = 1.96

Using the relation :

(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)

(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)

Lower boundary :

-0.02 - 0.0833710 = −0.103371

Upper boundary :

-0.02 + 0.0833710 = 0.063371

(−0.103371 ; 0.063371)

B.)

We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.

C.)

For sample size :

n1 = 300 ; n2 = 250

(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)

Lower boundary :

-0.02 - 0.0263642 = −0.0463642

Upper boundary :

-0.02 + 0.0263642 = 0.0063642

( -0.0463642, 0.0063642)

7 0
2 years ago
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