Let V = the launch velocity
Let θ = the launch angle
Let d = the horizontal distance traveled
Ignore air resistance.
The horizontal component of velocity is
u = V cos θ
The time of flight is
t = d/(V cosθ) = (d/V) secθ
Create a table of θ versus t as shown below.
θ t/(d/V)
---- ----------
45 1.4142
40 1.3054
35 1.2208
30 1.1547
The graph shows that as the launch angle decreases below 45°, the time of flight decreases.
Therefore arrow b (θ < 45°) arrives first.
Answer: Arrow b arrives first.
Hey there!!
Given equation :
11x² + 35x + 6
Now let's write 35x as 33x and 2x
Then the equation would become :
... 11x² + 33x + 2x + 6
... Now, let's take the common terms 11x² + 33x and 2x + 6
It would become :
... 11x ( x + 3 ) + 2 ( x + 3 )
... Now, we will write this as :
... ( 11x + 2 ) ( x + 3 )
Hence, this is as the answer...
Hope my answer helps!!
Answer:x=4.2643
Step-by-step explanation:
tan35degrees=x/9
9(tan35degrees)=x
4.2643=x
Answer:
3x-2
Step-by-step explanation:
3 times a number is 3x, if we use x as the number
Two less than (3x) is 3x - 2
