Answer: 20) 2365 g
21) 22.39 grams.
22) 29.99 g
Explanation: 20) molarity is the no of moles of solute per unit volume.
We can calculate amount of CaCl2 required to prepare 0.1 M CaCl2 1000 ml solution.
we know that to prepare one ltr of 1 M solution of CaCl2 111 g required
Now consider x gram will require to prepare to
so that comparing above both condition
1000ml ×1M×X g=1000ml×0.1M×111g
X= 11.1 gram
X= 11.1 g of CaCl2
Hence 11.1 g of CaCl2 would be dissolved in 1.0L of a 0.100 M solution of CaCl2
21) How many moles of CaCl₂ in that solution?
;
;
.
What's the mass of that 0.20172 moles of CaCl₂?
Molar mass from a modern periodic table:
Ca- 40.078;
Cl- 35.45.
Molar mass of CaCl₂:
.
Mass of that 0.20172 moles of CaCl₂:
22) its a 3.0m solution so 1 litre of solution contains 3 moles of NaOH, 250ml of solution contains 0.25x39.9971 g/mol, so 250ml of this solution contains 0.75x39.9971=29.99g, or if you round it up 30.0g
That is a chemical change
Answer:
v = distance/time = 60m/20s = 3 m/s
Answer:
The first step of this ozonolysis produces an acid anhydrous with on hydrolysis gives the same Carboxylic acid
Explanation:
Please find attached the reaction steps
<u>Answer:</u> The number of phosphorus atoms in given amount of copper(II) phosphate is 
<u>Explanation:</u>
We are given:
Moles of copper(II) phosphate 
= 7.00 mol
1 mole of copper(II) phosphate contains 3 moles of copper, 2 moles of phosphorus and 8 moles of oxygen atoms
Moles of phosphorus in copper(II) phosphate = 
According to the mole concept:
1 mole of a compound contains 
number of particles
So, 7.00 moles of copper(II) phosphate will contain = 
number of phosphorus atoms.
Hence, the number of phosphorus atoms in given amount of copper(II) phosphate is
