The volume in liters occupied by 22.6 g of I₂ gas at STP is 1.99 L (answer A)
<u><em>calculation</em></u>
Step: find the moles of I₂
moles= mass÷ molar mass
from periodic table the molar mass of I₂ is 253.8 g/mol
moles = 22.6 g÷253.8 g/mol =0.089 moles
Step 2:find the volume of I₂ at STP
At STP 1 moles =22.4 L
0.089 moles= ? L
<em>by cross multiplication</em>
={ (0.089 moles x 22.4 L) /1 mole} = 1.99 L
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Answer:
A mixture
Explanation:sorry if its wrong
Answer:
.176 M
Explanation:
set the number of moles of the base equal to the number of moles of acid.
(1.008 mol/L)(26.23 x 10^-3 L)=(150.2x10^-3 L)(x)
x = .176030892 mol/L
Answer:
(C) im pretty sure is the answer
Explanation:
