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r-ruslan [8.4K]
3 years ago
11

What is the melting point of stainless steel?

Chemistry
1 answer:
Mashcka [7]3 years ago
6 0
<span>"Alloy additions also suppress (lower) the melting range. Pure iron (Fe) has a fixed melting point of 1535°C, chromium (Cr) 1890°C and nickel (Ni) 1453°C compared to a range of 1400-1450 °C for type 304 stainless steel."</span>
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When you push or pull something, you are creating
Katarina [22]

force but could be tension

3 0
2 years ago
Which statement best describes the pH of pure water?
Ray Of Light [21]

The pH of pure water is neutral because the concentration of hydronium ions equals that of hydroxide ions.

Answer: Option A

<u>Explanation:</u>

Water is one of the most important constituents of living being. It is said that there is no life without water. So that water need to neutral in nature to save life. Pure water is composed of hydronium H^{+} and hydroxide \left(O H^{-}\right) ions. It is known that hydronium ions are acidic in nature with concentration of 1 \times 10^{-7} \mathrm{M} / \mathrm{L}.

Similarly, the hydroxide ions which are basic in nature will be in same concentration as that of hydronium ions. So, as the concentration of basic and acidic elements are equal with the same strength of pH, the combination of these ions lead to formation of pure water with the pH being neutral.

7 0
3 years ago
Read 2 more answers
If 23.5 g of ammonia (NH3) is dissolved in 1.0 L of solution, what is the molarity?
r-ruslan [8.4K]

Answer:

1.38 M

Explanation:

Need to use the Molarity equation M=n/L

23.5g/ 17.031g/mol NH3 = 1.38 moles

1.38 moles/ 1.0 L = 1.38 M

4 0
2 years ago
How many atoms of hydrogen are present in 2.92 g of water?
Wittaler [7]
The molecular weight of water is <span>18.01528 g/mol.
So in 2.92 grams there are 2.92/</span>18.01528 = 0.1621 mol of particles.

1 mol contains 6,02214 × 10^<span>23 particles by definition.

So the nr of H2O molecules is </span>0.1621 * 6,02214 × 10^23 = 0,9761 × 10^23.

Every molecule has 2 H atoms, so you have to double that.

2* 0,9761 × 10^23 = 1.952 × 10^23.
3 0
3 years ago
Read 2 more answers
You have a radioactive isotope with a mass of 400 grams. The sample has a half life of 5 days. How much is left after 25 days ha
Alexeev081 [22]

Answer:

Amount left after 25 days = 12.5 g

Explanation:

Given data:

Mass of sample = 400 g

Half life of sample = 5 days

Mass left after 25 days = ?

Solution:

First of all we will calculate the number of half lives passes in given time period.

Number of half lives = Time elapsed / Half life

Number of half lives = 25 days/ 5 days

Number of half lives = 5

At time zero = 400 g

At 1st half life = 400 g/2 = 200 g

At 2nd half life = 200 g/2 = 100 g

At 3rd half life = 100 g/2 = 50 g

At 4th half life = 50 g/2 = 25 g

At 5th half life = 25 g/2 = 12.5 g

4 0
3 years ago
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