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3 years ago

If the initial temperature of a movable cylinder was 50 degrees Celsius

Chemistry

1 answer:

slega [8]3 years ago

5 0

Answer:

8.45 L

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 50 °C

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 0 °C

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 50 °C

Initial temperature (T₁) = 50 °C + 273

Initial temperature (T₁) = 323 K

Final temperature (T₂) = 0 °C

Final temperature (T₂) = 0 °C + 273

Final temperature (T₂) = 273 K

Finally, we shall determine the new volume. This can be obtained as follow:

Initial temperature (T₁) = 323 K

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 273 k

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

2 × 5 / 323 = 1 × V₂ / 273

10 / 323 = V₂ / 273

Cross multiply

323 × V₂ = 10 × 273

323 × V₂ = 2730

Divide both side by 323

V₂ = 2730 / 323

V₂ = 8.45 L

Thus, the new volume is 8.45 L

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Explanation:

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3 years ago

Write the balanced chemical equation for the reaction between aqueous sodium carbonate and

ioda

Answer:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

Explanation:

This question is asking to write and balance an equation between between aqueous sodium carbonate (Na2CO3) and aqueous nitric acid (HNO3). The equation is as follows:

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3 years ago

Consider the following four structures: What is the relationship of I and II? What is the relationship of I and III? What is the

daser333 [38]

Answer:

The different structures are shown in the attachment.

I and II - structural isomers

I and III - Structural isomers

I and IV - structural isomers

II and III - structural isomers

II and IV - structural isomers

III and IV - stereoisomers

Explanation:

The knowledge of Isomerism is tested here; there are two types of isomerism ; structural and stereoisomerism.

Structural Isomers have similar molecular and different double bond positioning, these occurs mostly in ALKENE FAMILY.

Stereo-isomers have the same molecular formular and similar patterns but differ in their spatial arrangement. trans and cis are typical examples of stereo-isomers.

From the question; Relationship between I and II is that they are structural isomers since they have the same molecular formula, but different bond atom arrangement and infact they are the same compound.

Relationship between I and III is that they are structural isomers with similar molecular formular but differ in the double bond position.

Relationship between I and IV is that they are structural isomers with similar molecular formula but different double bond arrangement.

Relationship between II and III is that they are structural isomers with similar molecular formular but different double bond position

Relationship between II and IV is that they are also structural isomers with the same molecular formular but different double bond position.

Relationship between III and IV is that they are stereo-isomers with same molecular formula but different spatial arrangement, hence cis and trans.

4 0

3 years ago

Write the equilibrium constant expression for the reaction below.

kodGreya [7K]

Answer:

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

Explanation:

The equilibrium constant indicates the % of the yield reaction and can shows where the reaction is going to be equilibrated.

It works with molar concentrations on the equilibrium and it does not consider the solids compounds

Kc also can be modified by the time of the reaction.

This reaction is:

CS₂ (g) + 4 H₂O(g) ⇌ CH₄ (g) + 2H₂S (g)

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

8 0

2 years ago

Cho m gam FeO tác dụng hết với dung dịch H2SO4, thu được 200 ml dung dịch FeSO4 1M. Giá trị của m là

BaLLatris [955]

Answer: The mass of $FeO$ required is 14.37 g

Explanation:

Molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}$ ......(1)

We are given:

Molarity of iron (II) sulfate = 1 M

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Putting values in equation 1, we get:

$\text{Moles of }FeSO_4=(1mol/L\times 0.200L)=0.200mol$

The chemical equation for the reaction of FeO with sulfuric acid follows:

$FeO+H_2SO_4\rightarrow FeSO_4+H_2O$

By stoichiometry of the reaction:

If 1 mole of iron (II) sulfate is produced by 1 mole of FeO

So, 0.200 moles of iron (II) sulfate will produce = $\frac{1}{1}\times 0.200=0.200mol$ of FeO

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We know, molar mass of $FeO$ = 71.84 g/mol

Putting values in above equation, we get:

$\text{Mass of }FeO=(0.200mol\times 71.84g/mol)=14.37g$

Hence, the mass of $FeO$ required is 14.37 g

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3 years ago