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Nikitich [7]
3 years ago
7

Baking a cake is an example of -

Chemistry
1 answer:
ss7ja [257]3 years ago
5 0
I think the correct answer is D. Baking a cake is an example of endothermic reaction. The chemical changes happening when you bake a cake includes denaturing proteins in milk, eggs, and flour. Chemical bonds are broken and new bonds are made. To aid these changes, heat is supplied by the heat in an oven.<span />
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What is the volume of 12.0 grams of oxygen gas at STP<br><br> Atomic mass:O = 15.99 grams/moles
strojnjashka [21]

Answer:

16.82 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 1.0 atm, STP conditions).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = mass/molar mass = (12.0 g)/(15.99 g/mol) = 0.7505 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 0.0°C + 273 = 273.0 K, STP conditions).

<em>∴ V = nRT/P</em> = (0.7505 mol)(0.0821 L.atm/mol.K)(273.0 K)/(1.0 atm) = <em>16.82 L.</em>

6 0
4 years ago
Please explain, I don't understand.
BartSMP [9]

Answer:

7. A) I, II ; 8. D) 2.34e9 kJ

Step-by-step explanation:

7. Combustion of ethanol

I. The negative sign for ΔH shows that the reaction is exothermic.

II. The enthalpy change would be different if gaseous water were produced.

That's because it takes energy to convert liquid water to gaseous water, and this energy is included in the value of ΔH.

III. The reaction is a redox reaction, because

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IV. The products of the reaction occupy a smaller volume than the reactants, because 3 mol of gaseous reactant are forming 2 mol of gaseous product.

Therefore, only I and II are correct.

7. Hindenburg

Data:

  V = 2.00 × 10⁸ L

  p = 1.00 atm

  T = 25.1 °C

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Calculations:

(a) Convert temperature to kelvins

T = (25.1 + 273.15) K = 298.25 K

(b) Moles of hydrogen

Use the <em>Ideal Gas Law</em>:

pV = nRT

n = (pV)/(RT)

n = (1.00 × 2.00 × 10⁸)/(0.082 06 × 298.25) = 8.172 × 10⁶ mol

(c) Heat evolved

q = nΔH = 8.172 × 10⁶ × (-286) = -2.34 × 10⁹ kJ

The hydrogen in the Hindenburg released 2.34e9 kJ .

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