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Morgarella [4.7K]
2 years ago
7

Q3. Recall the equation that links gravitational field strength, mass and weight

Physics
1 answer:
Ierofanga [76]2 years ago
7 0
Gravitational potential energy = mass x gravitational field strength (g) x height
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What kind of lens is there in our eyes? where does it form the image of an object?​
Goshia [24]

Answer:

convex lens

Explanation:

An image is form in retina with light rays converging most at cornea and upon entering and existing the lens.Rays from top and bottom of the object are traced and produce an inverted image on the retina

8 0
2 years ago
How is the density of a substance calculated?
den301095 [7]
1).  Take a sample of the substance.  The sample should be the largest
possible that will allow it to be be easily handled and the following steps
to be performed with it. 
(The density doesn't depend on the size of the sample, and every sample
of the same substance has the same density.  But using a larger sample
can improve the accuracy of the measurements you make, and therefore
improve the accuracy of the density you derive for the substance.)

2). Ask or measure the mass of the sample.

3). Ask or measure the volume of the sample.

4). Divide the mass by the volume. Their quotient is the density
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3 0
3 years ago
In which position are the earth, moon, and sun during a full moon?
Arte-miy333 [17]

Answer:

The answer is B, although technically that is an eclipse.

5 0
3 years ago
The smallest part of an element that can still be identified as that element is a(n) _____.
romanna [79]
It’s an Atom so this is the answer
6 0
3 years ago
A spaceship moves at a speed of 0.95 c away from the Earth. It shoots a star wars torpedo toward the Earthat a speed of 0.90 c r
wariber [46]

Answer:

0.345 c

Explanation:

v_{se} = velocity of spaceship relative to earth = 0.95 c

v_{ts} = velocity of torpedo relative to spaceship = - 0.90 c

v_{te} = velocity of torpedo relative to earth

Velocity of torpedo relative to earth is given as

v_{te}=\frac{v_{se} + v_{ts}}{1 + \frac{v_{se}v_{ts}}{c^{2}}}

v_{te}=\frac{0.95c + (- 0.90 c)}{1 + \frac{(0.95 c)(- 0.90 c))}{c^{2}}}

v_{te} = 0.345 c

5 0
3 years ago
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