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Morgarella [4.7K]
3 years ago
7

Q3. Recall the equation that links gravitational field strength, mass and weight

Physics
1 answer:
Ierofanga [76]3 years ago
7 0
Gravitational potential energy = mass x gravitational field strength (g) x height
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A steel bridge is 1000 m long at -20°C in winter. What is the change in length when the temperature rises to 40°C in summer? The
xenn [34]

Answer:

ΔL = 0.66 m

Explanation:

The change in length on an object due to rise in temperature is given by the following equation of linear thermal expansion:

ΔL = αLΔT

where,

ΔL = Change in Length of the bridge = ?

α = Coefficient of linear thermal expansion = 11 x 10⁻⁶ °C⁻¹

L = Original Length of the Bridge = 1000 m

ΔT = Change in Temperature =  Final Temperature - Initial Temperature

ΔT = 40°C - (-20°C) = 60°C

Therefore,

ΔL = (11 x 10⁻⁶ °C⁻¹)(1000 m)(60°C)

<u>ΔL = 0.66 m</u>

6 0
4 years ago
How long does it take to drive from one end of california to the other?
evablogger [386]

California is the third largest state and the only two bigger states than California are Alaska and Texas so it really depends on how you want to cross it. There are two routes to cross California depending on how you plan your visit and places you need to see. Depending on the route you take crossing California can take from twelve to almost sixteen hours of drive. 

8 0
3 years ago
Factors that affect pressure in fluid​
satela [25.4K]

Answer:

The factors that affect are depth of the fluid and its density

5 0
4 years ago
The tub of a washer goes into its spin cycle, starting from rest and gaining angular speed steadily for 7.00 s, at which time it
Keith_Richards [23]

Answer:

The no. of revolutions does the tub turn while it is in motion is = 52.51 revolutions

Explanation:

Given data

\omega_1 = 0

\omega_2 = 5 \frac{rev}{sec}

Time taken = 7 sec

(1). The angular acceleration is given by

\alpha = \frac{d \omega}{dt}

\alpha  = \frac{5}{7}

\alpha  = 0.714 \frac{rev}{s^{2} }

We know that from the equation of motion

\omega_2^{2} =  \omega_1^{2} + 2 \alpha \theta_1

5^{2} = 0 + 2 (0.714) \theta_1

\theta_1 = 17.5 \ rev  -------- (1)

(2). The angular acceleration is given by

\alpha = \frac{d \omega}{dt}

\alpha = - \frac{5}{14}

\alpha = - 0.357 \frac{rev}{s^{2} }

We know that from the equation of motion

\omega_2^{2} =  \omega_1^{2} + 2 \alpha \theta_2

0^{2} = 5^{2} + 2 (-0.357) \theta_2

\theta_2 = 35.01 rev  -------  (2)

Total no of revolution made by the machine is

\theta = \theta_1 + \theta_2

\theta = 17.5 + 35.01

\theta = 52.51 rev

Therefore the no. of revolutions does the tub turn while it is in motion is = 52.51  rev

8 0
3 years ago
A block with mass m =6.9 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.24 m.
Burka [1]
U need to set up n solve the general eqn for simple harmonic motion:
x" = -(k/m)x

solution is x(t) = (x0)*cos(wt) + (v0/w)*sin(wt)
where w=sqrt(k/m), x0 is x-position at t=0 and v0 is vel at t=0
u already calculated f in Q.2 and w = 2*pi*f
x0 is 0 as it starts at eqm
v0 is given at 5.1

so u have x(t)

vel is given by x'(t) = (x0)*(-w)*sin(wt) + (v0/w)*w*cos(wt)

substitute t=0.32, x0=0, v0=5.1 n w in the above, u can solve for v at t=0.32.

5 0
3 years ago
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