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3 years ago

Does altitude has an effect on weight? PLEASE HELP!

Physics

1 answer:

Studentka2010 [4]3 years ago

4 0

Answer:

Yes

Explanation:

The farther something is from the center of mass of an object such as a planet, the lower the gravitational force between them

F = GMm/d²

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A sprinter starts from rest and runs with constant acceleration to a top speed of 12m/s in 4.0 seconds.

bagirrra123 [75]

Answer:

a = 3,0 m/s²

Explanation:

En este ejercicio se pide calcular la aceleracion del cuerpo, usemos las ecuaciones de cinematica en una dimensión.

v= v₀ + a t

como el corredor parte del reposo si velocidad inicial es cero

v = at

a = v/t

calculemos

a = 12 /4,0

a = 3,0 m/s²

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3 years ago

14. Which of the following is an example of

Murljashka [212]

Answer:

none of the above or screwdriver

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2 years ago

As seen in the figure, a bullet with mass of 15.0-g is fired vertically and penetrates a block with mass of 2.5-kg and the block

rodikova [14]

Answer:

KE = 2.03 J

Explanation:

After impact, the kinetic energy of the bullet+block will convert to potential energy

½mv² = mgh

v = √(2gh) = √(2(9.81)(0.00500) = 0.0981 m/s

conservation of momentum during the collision

0.015u + 2.50(0) = (2.50 + 0.015)(0.0981)

u = 16.4481 m/s

KE = ½mv² = ½(0.015)16.4481² = 2.0290499...

KE = 2.03 J

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3 years ago

Please help! I will give brainliest!

irakobra [83]

Answer:

velocity because it says you are going 3 miles north and velocity is something going a speed in a certian direction

Explanation:

3 0

3 years ago

You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.

tatiyna

(a) $2.7\cdot 10^{25} kg$

The acceleration due to gravity on the surface of the planet is given by

$g=\frac{GM}{R^2}$ (1)

where

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

Here we know:

$g=22.4 m/s^2$

$d=1.8\cdot 10^7 m$ is the diameter, so the radius is

$R=\frac{d}{2}=\frac{1.8\cdot 10^7 m}{2}=9\cdot 10^6 m$

So we can re-arrange eq.(1) to find M, the mass of the planet:

$M=\frac{gR^2}{G}=\frac{(22.4 m/s^2)(9\cdot 10^6 m)^2}{6.67\cdot 10^{-11}}=2.7\cdot 10^{25} kg$

(b) $4.8\cdot 10^{31}kg$

The planet is orbiting the star, so the centripetal force is equal to the gravitational attraction between the planet and the star:

$m\frac{v^2}{r}=\frac{GMm}{r^2}$ (1)

where

m is the mass of the planet

M is the mass of the star

v is the orbital speed of the planet

r is the radius of the orbit

The orbital speed is equal to the ratio between the circumference of the orbit and the period, T:

$v=\frac{2\pi r}{T}$

where

$T=402 days = 3.47\cdot 10^7 s$

Substituting into (1) and re-arranging the equation

$m\frac{4\pi r^2}{rT^2}=\frac{GMm}{r^2}\\\frac{4\pi r}{T^2}=\frac{GM}{r^2}\\M=\frac{4\pi r^3}{GMT^2}$

And substituting the numbers, we find the mass of the star:

$M=\frac{4\pi^2 (4.6\cdot 10^{11} m)^3}{(6.67\cdot 10^{-11})(3.47\cdot 10^7 s)^2}=4.8\cdot 10^{31}kg$

4 0

3 years ago

Does altitude has an effect on weight? PLEASE HELP!​

Does altitude has an effect on weight? PLEASE HELP!