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2 years ago

How much work is done by an applied force to lift a 45 newton block 6.0 meters at a constant speed ?

Physics

1 answer:

AleksandrR [38]2 years ago

7 0

Answer:

270Joues

Explanation:

Step one:

given data

Force F= 45N

distance moved d= 6m

Required

The work done in moving the block 6m

Step two:

We know that the expression for the work done is

WD= force* distance

WD= 45*6

WD=270Joues

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The roller coaster car has a mass of 700 kg, including its passenger. If it is released from rest at the top of the hill A, dete

sweet [91]

Answer:

$h = 18.75 m$

Now when it will reach at point B then its normal force is just equal to ZERO

$N_B = 0$

$F_n = 1.72 \times 10^4$

Explanation:

Since we need to cross both the loops so least speed at the bottom must be

$v = \sqrt{5 R g}$

also by energy conservation this is gained by initial potential energy

$mgh = \frac{1}{2}mv^2$

$v = \sqrt{2gh}$

so we will have

$\sqrt{2gh} = \sqrt{5Rg}$

now we have

$h = \frac{5R}{2}$

here we have

R = 7.5 m

so we have

$h = \frac{5(7.5)}{2}$

$h = 18.75 m$

Now when it will reach at point B then its normal force is just equal to ZERO

$N_B = 0$

now when it reach point C then the speed will be

$mgh - mg(2R_c) = \frac{1}{2]mv_c^2$

$v_c^2 = 2g(h - 2R_c)$

$v_c = 13.1 m/s$

now normal force at point C is given as

$F_n = \frac{mv_c^2}{R_c} - mg$

$F_n = \frac{700\times 13.1^2}{5} - (700 \times 9.8)$

$F_n = 1.72 \times 10^4$

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3 years ago

Which of the following takes place in the combustion chamber of a gas turbine engine?A. A glow plug is used to add enough heat t

erica [24]

Answer:

Fuel oil is mixed with a proper portion of compressed air

Explanation:

A gas turbine has three main part, which are

combustion chamber
air compressor
power turbine

The combustion chamber is responsible for mixing fuel with a proper portion of compressed air.

The air compressor supplies air in sufficient quantity to satisfy the requirements of the combustion chamber

The power turbine produces the power to drive the air compressor.

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3 years ago

Which formula can be used to find the tangential speed of an orbiting object?

Luden [163]

The correct formula for calculating the tangential speed of an orbiting object is V(t)=wr.
V(t)= Tangential Speed
w= Angular Velocity
r= Radius of the Path

Hope this helps.

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3 years ago

Read 2 more answers

What best describes a recessive Allele

steposvetlana [31]

It means that the person has gotten two types of the same allele from each parent. ... If there is only one recessive allele that is received from one parent, then it will not manifest through the person but the person will also become a carrier.

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2 years ago

People often think that Galileo dropped two objects of dramatically different mass off of the Leaning Tower of Pisa that both hi

kramer

Answer: because of air resistance. See explanation for further details.

Explanation: Galileo performed an experiment to proof that the time of descent of two different masses is independent of time.

But in reality this is most likely not true because of air resistance and other fluid frictional effects in consideration.

If the experiment is performed in a vacuum, it will always be true that time is independent of masses of two falling objects.

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3 years ago