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adoni [48]
3 years ago
11

Your fingernail grows at a rate of about 0.1 mm per day. How many inches do your fingers grow per year?

Physics
1 answer:
forsale [732]3 years ago
6 0

Answer:

1.44

Explanation:

0.1mm x 365 = 3.65mm

3.65mm into inches is 1.44

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Which force stops the car from moving?
Alex73 [517]

Answer:

The force of friction.

Explanation:

Gravity keeps the car on the ground.

Motion Allows the car to move.

The force of speed doesnt make sense.

Friction would cause the car to stop moving.

8 0
2 years ago
Read 2 more answers
Two forces act at a point in the plane. The angle between the two forces is given. Find the magnitude of the resultant force. fo
Zielflug [23.3K]

Answer:

408N at 89.89°

Explanation:

This problem requires that we resolve the force vectors into

x- and y

-componentsOnce this is done, we can add the components easily, as the one 2-dimensional problem will be two 1-dimensional problems.

Finally, we will convert the resultant force into standard form and find the equilibrant.

Resolve into components:

F1x =F1cos 180°= 232(−1)=−232N

F1y=F1sin180°=0N

F2x=F2cos(−140°)=194(−0.766)=−148.6N

F1y=F1sin(−140°)=232(−0.643)=−149.17N

Note the change of the angle used to give the direction of

F2. Standard angles (rotation from thex

-axis; counterclockwise is +) should be used to avoid sign errors in the results.

Now, we add the components:

Fx=F1x+F2x=−380.6N

Fy=F1y+F1y=−148.17N

Technically, this is the resultant force. However, it should be changed back into standard form. Here's how:

F=√(Fx)2(Fy)2=√(−380.6)^2(−148.17)^2=408N

θ=tan−1(−148.17−380.6)

=89.89°

4 0
3 years ago
What is the relationship between lightning and thunder
PtichkaEL [24]
Whenever lightning strikes it separates the air where it goes. This air then rushes back together making a loud noise when it connects, creating thunder.
6 0
3 years ago
You throw a rock up into the air as hard as you can. It stays in the air a total of 6.0 s. What
vaieri [72.5K]

Answer:

<h2>5.9 x 10</h2>

Explanation:

6 0
3 years ago
A 0.20 kg mass on a horizontal spring is pulled back a certain distance and released. The maximum speed of the mass is measured
xxMikexx [17]

Answer:

b. 0.20 m/s.

Explanation:

Given;

initial mass, m = 0.2 kg

maximum speed,  v = 0.3 m/s

The total energy of the spring at the given maximum speed is calculated as;

K.E = ¹/₂mv²

K.E = 0.5 x 0.2 x 0.3²

K.E = 0.009 J

If the mass is changed to 0.4 kg

¹/₂mv² = K.E

mv² = 2K.E

v = \sqrt{\frac{2K.E}{m} } \\\\v =  \sqrt{\frac{2\times 0.009}{0.4} } \\\\v = 0.21 \ m/s\\\\v \approx 0.20 \ m/s

Therefore, the maximum speed is 0.20 m/s

4 0
3 years ago
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