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Lana71 [14]
3 years ago
14

Ammonia and oxygen react to form nitrogen and water, like this:

Chemistry
1 answer:
Dima020 [189]3 years ago
8 0

Answer:

1. A. Zero.

2. D. Greater than zero, and greater than the rate of the reverse reaction.

3. C. Greater than zero, and equal to the rate of the reverse reaction.

4. A. Some, but less than 237. mmol.

Explanation:

Before reactants are added in a system the rate of reaction is zero. This is because, the initial rate of reaction depends on the concentration of the reacting species in the system.

When the reactants are first added, the rate of forward reaction increases rapidly and is far greater than the rate of reverse reaction.

However, at equilibrium, the rate of forward reaction is equal to the rate of reverse reaction.

At equilibrium, some NH3 has been used and some will still remain in the system because the reaction is reversible.

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If 42.7 of 0.208 M hydrochloric acid are needed to completely neutralize a solution of calcium hydroxide, how many grams of calc
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Answer:

0.329 g

Explanation:

In the context of this problem, we have a chemical reaction between hydrochloric acid and calcium hydroxide. HCl is the acid here and calcium hydroxide is the base. Hence, we have an acid-base reaction, also known as neutralization reaction.

In a neutralization reaction, water is produced as a product, as well as a salt that we obtain after we exchange the cations: calcium bonds to chloride and hydrogen bonds to hydroxide (the latter is the formation of water). This means we also produce calcium chloride as a product. The overall reaction represents this as:

Ca(OH)_2(aq)+2 HCl (aq)\rightarrow CaCl_2 (aq)+2 H_2O (l)

Firslt of all, we wish to find the number of moles of HCl present. Having molarity and volume, this is done by applying the molarity formula. It states that molarity is equal to the rate between moles and volume:

c_{HCl}=\frac{n_{HCl}}{V_{HCl}}

Rearranging for moles of HCl, n:

n_{HCl}=c_{HCl}V_{HCl}

Based on stoichiometry of the balanced chemical equation, notice that 1 mole of calcium hydroxide reacts with 2 moles of HCl, meaning:

n_{Ca(OH)_2}=\frac{1}{2} n_{HCl}=\frac{1}{2}c_{HCl}V_{HCl}

Now that we have the expression for moles, we may also express moles of calcium hydroxide as the ratio between its mass and molar mass:

n_{Ca(OH)_2}=\frac{m_{Ca(OH)_2}}{M_{Ca(OH)_2}}

Using the last two equations, we see that:

\frac{1}{2}c_{HCl}V_{HCl}=\frac{m_{Ca(OH)_2}}{M_{Ca(OH)_2}}\\\therefore m_{Ca(OH)_2}=\frac{1}{2}c_{HCl}V_{HCl}M_{Ca(OH)_2}

Substitute the given data, as well as the molar mass of calcium hydroxide:

m_{Ca(OH)_2}=\frac{1}{2}\cdot0.208 M\cdot0.0427 L\cdot74.093 g/mol=0.329 g

8 0
3 years ago
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