All categories

2 years ago

If you take a part time job while you are still in school what might your opportunity scost be

2 answers:

7 0

The opportunity costs of working part-time while attending high school could be studying time, grades, and your own free time. It depends on the person, how they do in school, but if it were for me, I would say the benefits outweigh the costs. I have enough time to study and still get good grades in school.

Viefleur [7K]2 years ago

4 0

Answer:

I don't know I'm rich student

Explanation:

sorry

You might be interested in

Write a balanced chemical equation showing how each metal oxide reacts with HCl. SrO Na2O Li2O BaO

Agata [3.3K]

Answer:

See below

Explanation:

Each metal oxide reacts with HCl to form water and the metal chloride

$\rm SrO + 2HCl \longrightarrow SrCl_{2} + H_{2}O\\\\Na_{2}O + 2HCl \longrightarrow 2NaCl + H_{2}O\\\\Li_{2}O + 2HCl \longrightarrow 2LiCl + H_{2}O\\\\BaO + 2HCl \longrightarrow BaCl_{2} + H_{2}O$

6 0

3 years ago

Read 2 more answers

PLEASE HELP AGAIN lol thank you :))

Annette [7]

BBBBBBBBBBBBBBBBBBBBBBBBBBBBB

8 0

3 years ago

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

scoray [572]

Answer:

70.77 g/mol is the molar mass of the unknown gas.

Explanation:

Effusion is defined as rate of change of volume with respect to time.

Rate of Effusion= $\frac{Volume}{Time}$

Effusion rate of oxygen gas after time t = $E=\frac{4.64 mL}{t}$

Molar mass of oxygen gas = M = 32 g/mol

Effusion rate of unknown gas after time t = $E'=\frac{3.12 mL}{t}$

Molar mass of unknown gas = M'

The rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{E}{E'}=\sqrt{\frac{M'}{M}}$

$\frac{\frac{4.64 mL}{t}}{\frac{3.12 mL}{t}}=\sqrt{\frac{M'}{32 g/mol}}$

M' = 70.77 g/mol

70.77 g/mol is the molar mass of the unknown gas.

8 0

3 years ago

HNO3 + H2O → H3O^+ + NO3 which ones are acids and which ones are bases

nlexa [21]

Answer:

HNO₃ and H₃O⁺ are acids

H₂O and NO₃⁻ are bases

Explanation:

The chemical equation is:

HNO₃ + H₂O → H₃O⁺ + NO₃⁻

There are several definitions of acid and bases: Arrhenius', Bronsted-Lowry's and Lewis'.

Bronsted-Lowry model defines and acid as a donor of protons, H⁺.

In the given equation HNO₃ is such substance: it releases an donates its hdyrogen to form the H₃O⁺ ion.

On the other hand, a base is a substance that accepts protons.

In the reaction shown, H₂O accepts the proton from HNO₃ to form H₃O⁺.

Thus, H₂O is a base.

In turn, on the reactant sides the substances can be classified as acids or bases.

H₃O⁺ contain an hydrogen that can be donated and form H₂O; thus, it is an acid (the conjugated acid), and NO₃⁻ can accept a proton to form HNO₃; thus it is a base (the conjugated base).

4 0

3 years ago

Balance the following chemical equation by providing the correct coefficients HBr+Ba(OH)2 ———— BaBr2+H2O

stealth61 [152]

Answer:

2HBr + Ba(OH)2 = BaBr2 + 2H20

4 0

3 years ago