Addition of 6q + 1 and q + 11 is 7q + 12
<em><u>Solution:</u></em>
Given that, we have to add the given two expressions
<em><u>Given expressions are:</u></em>
6q + 1 and q + 11
We have to add both the expressions
Addition of 6q + 1 and q + 11 = 6q + 1 + q + 11
Add the coefficients of same variable. Here "q" is present in two terms
Therefore, add 6q and q
Similarly, add the constants 1 and 11
<em><u>Thus finally addition is done as:</u></em>
Thus addition of 6q + 1 and q + 11 is 7q + 12
Answer:
See picture attached
Step-by-step explanation:
The graph of a non-proportional linear relationship is a line that does not cross through the origin. The graph of a proportional linear relationship does.
Given the general expression of a line: y = ax + b, where a and b are constants, if b is equal to zero, the line cross through the origin, otherwise the line inercept y-axis at value of b.
Direct variation means that y = kx, where k is a constant, then is a proportional linear relationship.
Given a cell phone company charges $19.95 per month for the first 2G, then $5 per gig over the initial 2G; the graph is a non-proportional linear relationship because the cost is never zero and the graph does not cross through the origin.
Given a cell phone company charges $29.95 per month always, then the cost is never zero and the graph does not cross through the origin.
