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vekshin1
3 years ago
12

Solid copper (II) oxide is placed in a sealed container with an excess of ammonia gas. When equilibrium is established the parti

al pressure of N2 is 0.255atm. The reaction is as follows: 3CuO (s) + 2 NH3 (g) ↔ 3 Cu (s) + N2 (g) + 3 H2O (g) a) What is the partial pressure of H2O (g) at equilibrium?
Chemistry
1 answer:
Paha777 [63]3 years ago
4 0

Answer:

0.765 atm is the partial pressure of H₂O (g) at equilibrium.

Explanation:

Considering the ICE table for the given equilibrium as:-

                        3CuO (s) + 2 NH₃ (g) ↔ 3 Cu (s) + N₂ (g) + 3 H₂O (g)

                       ------------------------------------------------------------------------------

t=teq                 a - 3P           b - 2P              3P          P            3P

Also, given that:-

Partial pressure of N₂ = 0.255 atm

From the above table, x = 0.255 atm

Thus, Partial pressure of H₂O = 3x = 3\times 0.255\ atm = 0.765 atm

<u>0.765 atm is the partial pressure of H₂O (g) at equilibrium.</u>

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The molality of the solution is obtained from;

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