Answer:
There are 29.4 grams of oxygen in the container
Explanation:
<u>Step 1: </u>Data given
Volume = 20.0 L
Pressure = 845 mmHg
Temperature = 22.0 °C
Molar mass of O2 = 32 g/mol
<u>Step 2:</u> Ideal gas law
p*V = n*R*T
⇒ p = the pressure of the gas = 845 mmHg = 1.11184
⇒ V = the volume of the gas = 20.0 L
⇒ n = the number of moles = TO BE DETERMINED
⇒R = the gasconstant = 0.08206 L*atm/K*mol
⇒ T = the temperature = 22°C + 273 = 295 Kelvin
n = (p*V)/(R*T)
n = (1.11184*20.0)/(0.08206*295)
n = 0.9186 moles
<u>Step 3:</u> Calculate mass of NO2
Mass of O2 = Moles O2 * Molar mass O2
Mass of O2 = 0.9186 moles * 32 g/mol
Mass of O2 = 29.4 grams
There are 29.4 grams of oxygen in the container
Answer:
Explanation:
Q = Ce . m .ΔT
Q : calor
Ce : calor especifico
m: masa
ΔT : variación de temperatura
capacidad térmica : 0,550 cal / °C
lectura :
por 1 °C se tiene 0,550 cal
por lo tanto tenemos datos de la temperatura y del calor
pero no olvidar las unidades en el sistema internacional :
Ce : J / kg . K
J: joules
kg: kilogramo
K: kelvin
pasar de gramos a kilogramos
pasar de calorías a joules
pasar de grado celsius a kelvin
1000g equivale a 1kg
15g equivale a 0,015 kg
K= °C + 273 ⇒ formula para pasar de grado celsius a kelvin
K= 1 + 273
K= 274
1 caloría equivale a 4,184 joules
0,550 caloría equivale a 2,3012 joules
ahora como todos los datos ya están en el S.I remplazamos en la formula
Q = Ce . m .ΔT
2,3012 = Ce . 0,015.274
Ce=0,5599 J / kg. K
Atomic number is same as the number of protons in the element which is further equal to the number of electrons. As the number of electrons increases in the element, the atomic number of the element also increases.
In periodic table, elements are arranged in the groups, and these groups are columns starting from 1 to 18, elements are arranged in increasing order of atomic number. Elements are placed with difference of one atomic number.
First four elements present in the periodic table is:
atomic number is one (1).
atomic number is two (2).
atomic number is three (3).
atomic number is four (4).
Thus, the series of atomic numbers that represents the ordering of consecutive elements within the periodic table is the last option - 1, 2, 3, 4...
A is the answer
Hope it helps :)
