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Value of g on the distant planet is 16 m/s²</h2>
Explanation:
We have equation of motion v² = u² + 2as
Here initial velocity, u = 2 m/s
Final velocity, v = 10 m/s
Displacement, s = 3 m
We need to find acceleration, a.
Substituting
v² = u² + 2as
10² = 2² + 2 x a x 3
6a = 96
a = 16 m/s²
Value of g on the distant planet is 16 m/s²
You’ve just been involved in a traffic accident that leaves you stranded on the side of the road. <u>Microwaves from the EM spectrum would be of the most use.</u>
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Explanation:
- Microwaves are a form of electromagnetic radiation with wavelengths ranging from about one meter to one millimeter, with frequencies between 300 MHz and 300 GHz.
- Microwaves have a range of applications, including communications, radar and, perhaps best known by most people, cooking
- Microwave is a line-of-sight wireless communication technology that uses high frequency beams of radio waves to provide high speed wireless connections that can send and receive voice, video, and data information.
- Microwaves and radio waves are used to communicate with satellites.
- Microwaves pass straight through the atmosphere and are suitable for communicating with distant geostationary satellites, while radio waves are suitable for communicating with satellites in low orbit.
- Microwaves are widely used in modern technology, <u>for example</u> : in point-to-point communication links, wireless networks, microwave radio relay networks, radar, satellite and spacecraft communication, medical diathermy and cancer treatment, etc
Answer:
m v^2 / R = G M m / R^2 gravitational attraction = centripetal force
M = v^2 R / G solving for M
period = 6 h 25 min = (6 * 3600 + 25 * 60) sec = 23,100 sec = T
v = 2 pi R / T
M = 4 pi^2 R^3 / (G T^2)
M = 39.5 * (8.6E7)^3 / (6.67E-11 * 2.31E4^2)
M = 39.5 * 636 / (6.67 * 5.34) * 10^24
M = 7.05 * 10^26 kg
A.) LUNAR MARIA..............
Change in velocity of larger moose: (1/3)v - v = -(2/3)v
<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>
<span>- (change in velocity of larger moose)/(change in velocity of smaller moose) = 2
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