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3 years ago

Which type of energy is released when a bond between atoms is broken

Physics

1 answer:

Murrr4er [49]3 years ago

4 0

Answer: gases

Explanation: because gases move around freely and they would be the only one to make sense because solid are compacted together and liquid are not so fast at moving but gases are wild

dont use this this is a bad explanation

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A wire carries a steady current of 2.60 A. A straight section of the wire is 0.750 m long and lies along the x axis within a uni

ad-work [718]

Answer:

The magnetic force on the section of wire is $-2.925\hat{j}\ N$ .

Explanation:

Given that,

Current $I = 2.60\hat{i}\ A$

Length = 0.750 m

Magnetic field $B = 1.50\hat{k}\ T$

We need to calculate the magnetic force on the section of wire

Using formula of magnetic force

$\vec{F}=l\vec{I}\times\vec{B}$

$\vec{F}=0.750\times2.60\hat{i}\times1.50\hat{k}$

Since, $\hat{i}\times\hat{k}=-\hat{j}$

$\vec{F}=-2.925\hat{j}\ N$

Hence, The magnetic force on the section of wire is $-2.925\hat{j}\ N$ .

7 0

3 years ago

The transfer of energy through varios stages in an ecological community is called

salantis [7]

It is called food chain

6 0

4 years ago

Read 2 more answers

What is the average power developed by a motor as it lifts a 400.-kilogram mass at constant speed through a vertical distance of

Tomtit [17]

Answer:

The average power developed by a motor is 4905 Watts.

Explanation:

The average power is given by:

$P = \frac{W}{t}$

Where:

W: is the work

t: is the time = 8.0 s

First, let's find the work:

$W = F*d$

Where:

F: is the force

d: is the displacement = 10.0 m

The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:

$F = mg = 400 kg*9.81 m/s^{2} = 3924 N$

Hence, the average power is:

$P = \frac{F*d}{t} = \frac{3924 N*10.0 m}{8.0 s} = 4905 J/s = 4905 W$

Therefore, the average power developed by a motor is 4905 Watts.

I hope it helps you!

3 0

3 years ago

A 88.6-kg wrecking ball hangs from a uniform heavy-duty chain having a mass of 26.9kg . (Use 9.80m/s2 for the gravitational acce

Dafna11 [192]

Answer:

Tension maximum =1131.9 N

Tension minimum =868.28 N

Tension at 3/4= 1065.995 N

Explanation:

Given Mass of wrecking ball M1=88.6 Kg

Mass of the chain M2=26.9 Kg

Maximum Tension Tension max=(M1+M2) × (9.8 m/s²)

=(88.6+26.9) × (9.8 m/s²)

=115.5 × 9.8 m/s²

Tension maximum =1131.9 N

Minimum Tension Tension minimum=Mass of the wrecking ball only × 9.8 m/s²

=88.6 × 9.8 m/s²

Tension minimum =868.28 N

Tension at 3/4 from the bottom of the chain =In this part you have to use 75% of the chain so you have to take 3/4 of 26.9

= (3/4 × 26.9)+88.9) × 9.8 m/s²

= (20.175+88.6) × 9.8 m/s²

=(108.775) × 9.8 m/s²

=1065.995 N

6 0

4 years ago

A roller coaster has a 100.0 kg cart at the top of a 22.0 m ramp. As it goes down the ramp, it change 800.0 joules of energy to

AlekseyPX

Answer:

d.20760 J

Explanation:

We are given that

Mass of cart=m=100 kg

At the top,h=22 m

Amount of energy convert into heat due to friction=E=800 J

We have to find the kinetic energy at the bottom of the ramp.

Potential energy drop=mgh= $100\times 9.8\times 22=21560 J$

Kinetic energy at the bottom=Potential energy drop-energy lost due to friction

Kinetic energy at the bottom =(21560-800) J

Kinetic energy at the bottom=20760 J

Hence, the kinetic energy at the bottom of the ramp=20760 J

d.20760 J

5 0

3 years ago