Answer:
5.6 L of hydrogen
Explanation:
when 5.6 liter is added of hydrogen, the value equallify and becomes right
The answer is -60.57 = -60.6 KJ.
CaC2(s) + 2 H2O(l) ---> Ca(OH)2(s) +C2H2(g) H= -127.2 KJ
Hf C2H2 = 226.77
Hf Ca(OH)2 = -986.2
<span>Hf H2O = -285.83
Now,
</span><span>add them up. 226.77 - 986.2 + (2*285.83) = -187.77
</span><span>Add back the total enthalpy that is given in the question
-187.77+127.2 = -60.57 </span>
Answer:The weight of Patterson on the moon would be less.
Explanation: It would be less because the moon has more mass.
Explanation:
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