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ExtremeBDS [4]
3 years ago
8

What is the density of iron if 5.0ml has a mass of 39.5g?

Chemistry
1 answer:
Kobotan [32]3 years ago
5 0

Answer:  p = m/Vp = 39.5 g/5.0 cm3p = 7.9 g/cm3 4.

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The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g)SO2(g) + Cl2(g) is first order in SO2Cl2. During one experime
krok68 [10]

Answer: The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample = 559 min

a = let initial amount of the reactant = 2.83\times 10^{-3}

a - x = amount left after decay process  = 3.06\times 10^{-4}

559min=\frac{2.303}{k}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=\frac{2.303}{559}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=3.96\times 10^{-3}min^{-1}

The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

6 0
3 years ago
When sodium carbonate is dissolved in water, it doesn’t dissociate, or break up, completely. There is always some sodium carbona
dusya [7]
It's a weak base because weak bases don't dissociate completely. If it did, then it would be a strong base.
7 0
3 years ago
How many milliliters of 0.0510 m edta are required to react with 50.0 ml of 0.0200 m cu2 ?
krok68 [10]
Cu  ions plus EDTA2-   ->cu(EDTA)2-  plus 2H-
   number  of  moles  of  CU  ions  used  which is   equal to  molarity  multiplied  by    volume  in  litres
that  is  50xo.o2  divided  by 1000  that  is  0.001moles
Since  ratio  is  1:1  the  moles  of EDTA  is  also0.001moles
volume  of  EDTA  is  0.001  divided  by  0.0510m  which  is  0.0196  litres in  ml is  0.0196x1000  which  is  19.61ml
4 0
3 years ago
An aluminum kettle weights 1.05 kg and has a heat capacity of 0.9211 J over grams Celsius how much heat is required to increase
Serggg [28]

Answer:

64799.4 J

Explanation:

The following data were obtained from the question:

Mass (M) = 1.05 kg = 1.05 x 1000 = 1050g

Specific heat capacity (C) = 0.9211 J/g°C

Initial temperature (T1) = 23°C

Final temperature (T2) = 90°C

Change in temperature (ΔT) = T2 – T1 =

90°C – 23°C = 67°C

Heat required (Q) =....?

The heat required to increase the temperature of the kettle can b obtain as follow:

Q = MCΔT

Q = 1050 x 0.9211 x 67

Q = 64799.4 J

Therefore, 64799.4 J of heat is required to increase th temperature of the kettle from 23°C to 90°C.

4 0
3 years ago
How many miles of C5H12 are there in 362.8 grams of the compound?
Dmitry_Shevchenko [17]

Answer:

5.03 moles

Explanation:

Find the molar mass of C5H12 and you will get 72.17 g/mol

Next to find the number of moles, you divide 362.8 by the molar mass and you get

(362.8 g)/(72.17 g/mol)= 5.03 moles

3 0
3 years ago
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