Answer:
-3.72 (or -3.70 depending on what values you used)
Explanation:
First, use the molar mass of Cl2 convert the mass of Cl2 to moles.
1.48 g Cl2(1 mol70.906 g)=0.02087 mol Cl2
Note that we are given ΔH=−886kJ. This refers to the enthalpy change associated with the reaction of 5mol of Cl2 by the balanced equation shown below.
2P+5Cl2⟶2PCl5ΔH=−886kJ
Therefore, to determine the enthalpy change associated with the reaction of 1.48gCl2, divide ΔH by 5molCl2 to determine the enthalpy change per mole of Cl2, then multiply by 0.02087 mol Cl2. (note: if you round up here to .021 mol of Cl2 you will get the final answer of -3.72 later)
0.02087 mol Cl2(−886 kJ5 mol Cl2)=−3.698 kJ
Rounding the answer should to three significant figures, we find that the enthalpy change associated with the reaction of 1.48gCl2 is −3.70 kJ.
Notice that coefficients in stoichiometric equations (indicating numbers of moles) are exact, so they do not constrain the number of significant figures.
Answer:
c) FAD is the oxidizing agent
Explanation:
The β-oxidation is a catabolic process where fatty acids are degraded into a final product: Acetil-CoA. In order this process occurres, the fatty acid chain is being removed from a pair of carbon atoms on each cycle
Before the β-oxidation takes place, the fatty acid molecule should be activated, so it can go through the mitochondrial membrane into (via a carnitine translocator)
Once the activated molecule is inside the mitochondrial matrix, it can go through the β-oxidation: the first step is the oxidation of the fatty acid, with the enzyme Acyl-CoA-dehydrogenase (this enzyme catalyzes the creation of a double bond between carbon-2 and carbon-3.
This enzyme has attached a coenzyme: FAD, which takes the electrons (from the fatty acid oxidation) and becomes a reduced component: FADH2:
Acyl-CoA + FAD ↔ trans-Δ2-enoyl-CoA + FADH2
The molarity of the potassium hydroxide required to neutralize 60.0 mL of 0.0100 M H3PO4 is 0.02M.
<h3>How to calculate molarity?</h3>
The molarity of a solution can be calculated using the following formula:
CaVa = CbVb
Where;
- Ca = concentration of acid
- Cb = concentration of base
- Va = volume of acid
- Vb = volume of base
60 × 0.0100 = 30 × Cb
0.6 = 30Cb
Cb = 0.6/30
Cb = 0.02M
Therefore, molarity of the potassium hydroxide required to neutralize 60.0 mL of 0.0100 M H3PO4 is 0.02M.
Learn more about molarity at: brainly.com/question/2817451
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Answer:
i am 6th grade i dont knew this
It is called terminal velocity. I hope it's right though...