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belka [17]
3 years ago
12

How much °f of 35°C ? help me please​

Chemistry
1 answer:
MakcuM [25]3 years ago
6 0

Answer: 95 degrees fahrenheit hope this helps :]

Explanation:

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At a certain temperature, the solubility of strontium arsenate, sr3(aso4)2, is 0.0560 g/l. what is the ksp of this salt at this
REY [17]
The solution for this problem is:
Get into moles first. .0560 grams over 540.8 grams per mole = 1.04 x l0^-4 moles 
Sr3(As04)2 = 3 Sr++(aq) plus 2 As04^-3(aq) 
Ksp = (Sr++)^3(As04^-3)^2 
(Sr++) = 3 X 1.04 x l0^-4= 3.11 x l0^-4 
(As04^-3) = 2 x 1.04 x l0^-4= 2.07 x l0^-4 
Ksp = (1.04 x l0^-4)^3 (2.07 x l0^-4)^2 which equals 4.82 x 10^-20
5 0
3 years ago
How many grams of aluminum oxide will you need to start with in order to make 6500 g of aluminum hydroxide?
kherson [118]

Answer:

Explanation:

2Al(s) + 3 2 O2(g) → Al2O3(s) And given the stoichiometry ...and EXCESS dioxygen gas...we would get 6.25⋅ mol of alumina. the which represents a mass... ...6.25 ⋅ mol ×101.96 ⋅ g ⋅ mol−1 molar mass of alumina ≡ 637.25 ⋅ g.

3 0
2 years ago
Read 2 more answers
4. Ammonia is produced by the chemical reaction of nitrogen and hydrogen. N2 (g) + 3H2(g) →→ 2NH3 (9) (A) Calculate the number o
Makovka662 [10]

Answer:

a) No. of moles of hydrogen needed = 5.4 mol

b) Grams of ammonia produced = 27.2 g

Explanation:

N_2 (g)  +  3H_2(g) \rightarrow 2NH_3 (g)

a)

No. of moles of nitrogen = 1.80 mol

1 mole of nitrogen reacts with 3 moles of hydrogen

1.80 moles of nitrogen will react with

                               = 1.80 × 3 = 5.4 moles of hydrogen

b)

No. of moles of hydrogen = 2.4 mol

It is given that nitrogen is present in sufficient amount.

3 moles of hydrogen produce 2 moles of NH_3

2.4 moles of hydrogen will produce

                              = \frac{2}{3} \times 2.4 = 1.6\ mol\ of\ NH_3

Molar mass of ammonia = 17 g/mol

Mass in gram = No. of moles × Molar mass

Mass of ammonia in g = 1.6 × 17

                                    = 27.2 g

7 0
3 years ago
Please i needed but Good
dsp73
It's 48 cubic meters
6 0
3 years ago
Calculate the second volumes. 51.7 L at 27 C and 90.9 KPa to STP
Arturiano [62]

The second volume : 42.2 L

<h3>Further explanation</h3>

Given

51.7 L at 27 C and 90.9 KPa

Required

The second volume

Solution

STP = P₂=1 atm, T₂=273 K

T₁ = 27 + 273 = 300 K

P₁ = 90.9 kPa = 0,897 atm

Use combine gas law :

P₁V₁/T₁ = P₂V₂/T₂

Input the value :

0.897 x 51.7/300 = 1 x V₂/273

V₂= 42.20 L

6 0
3 years ago
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