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Licemer1 [7]
3 years ago
9

CaCo3+2HCL Cacl2+h2o+co2

Chemistry
1 answer:
Rasek [7]3 years ago
6 0

Answer:

Here

Explanation:

This is an acid-base reaction (neutralization): CaCO3 is a base, HCl is an acid.

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According to Bowen's reaction series, crystal settling should result in the magma being separated in lower layers rich in the ea
monitta

Answer:

quartz and olivine

Explanation:

According to my research on studies made by different geologists on Bowen's reaction series, it is known that crystal settling should result in the magma being separated in lower layers rich in the early-formed quartz and olivine minerals.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0
4 years ago
Which ions are isoelectronic with Krypton?
Tresset [83]

Answer:

Bromine

Explanation:

Bromine with an atomic number of 35 acquires one electron to attain 36 electrons. This makes it isoelectronic with krypton.

5 0
3 years ago
Chromium-51 is a radioisotope that is used to assess the lifetime of red blood cells The half-life of chromium-51 is 27.7 days.
8090 [49]

Answer:

11.9g remains after 48.2 days

Explanation:

All isotope decay follows the equation:

ln [A] = -kt + ln [A]₀

<em>Where [A] is actual amount of the isotope after time t, k is decay constant and [A]₀ the initial amount of the isotope</em>

We can find k from half-life as follows:

k = ln 2 / Half-Life

k = ln2 / 27.7 days

k = 0.025 days⁻¹

t = 48.2 days

[A]  = ?

[A]₀ = 39.7mg

ln [A] = -0.025 days⁻¹*48.2 days + ln [39.7mg]

ln[A] = 2.476

[A] = 11.9g remains after 48.2 days

<em />

8 0
3 years ago
Somebody please answer
Zepler [3.9K]

Answer:

177 mmHg

Explanation:

Given that:

The sample of  a gas is with Pressure (1) P_1 = 500 mmHg

The initial temperature T_1 = 773 K

The final temperature T_2 = 273 K

Using ideal gas equation:

\dfrac{P_1}{T_1} = \dfrac{P_2}{T_2} \\ \\  \dfrac{500}{773} = \dfrac{P_2}{273} \\ \\  (136500) = 773 \times P_2 \\ \\ P_2 = \dfrac{136500}{773} \\ \\  P_2 = 176.58 \ mmHg \\ \\  \simeq 177 mmHg

7 0
3 years ago
0.415 g of an unknown triprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an
Arturiano [62]

Answer:

Explanation:

Initial burette reading = 1.81 mL

final burette reading = 39.7 mL

volume of NaOH used = 39.7 - 1.81 = 37.89 mL .  

37.89 mL of .1029 M NaOH is used to neutralise triprotic acid

No of moles contained by 37.89 mL of .1029 M NaOH

= .03789 x .1029 moles

= 3.89 x 10⁻³ moles

Since acid is triprotic ,  its equivalent weight = molecular weight / 3

No of moles of triprotic acid = 3.89 x 10⁻³ / 3

= 1.30   x 10⁻³ moles .

8 0
3 years ago
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