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Oliga [24]
1 year ago
11

(ii) Calculate the maximum mass of ethanol that could be obtained g from 30.0 g of glucose.

Chemistry
1 answer:
Step2247 [10]1 year ago
3 0

Taking into account the reaction stoichiometry, 15.33 grams ethanol could be obtained from 30 grams of glucose.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

C₆H₁₂O₆  → 2 C₂H₅OH + 2 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • C₆H₁₂O₆: 1 mole  
  • C₂H₅OH: 2 moles
  • CO₂: 2 moles

The molar mass of the compounds is:

  • C₆H₁₂O₆: 180 g/mole
  • C₂H₅OH: 46 g/mole
  • CO₂: 44 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • C₆H₁₂O₆: 1 mole ×180 g/mole= 180 grams
  • C₂H₅OH: 2 moles ×46 g/mole= 92 grams
  • CO₂: 2 moles ×44 g/mole= 88 grams

<h3>Mass of C₂H₅OH formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 180 grams of glucose form 92 grams of ethanol, 30 grams of glucose form how much mass of ethanol?

mass of ethanol=\frac{30 grams of glucosex 92 grams of ethanol}{180 grams of glucose}

<u><em>mass of ethanol= 15.33 grams</em></u>

Then, 15.33 grams ethanol could be obtained from 30 grams of glucose.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

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In order to gain one pound of body weight, the average person must consume 3500 more calories
Fed [463]

Answer:

<em>17500 calories</em> of chocolate bars are needed to eat to gain 5 pounds.

Explanation:

We can use ratios to calculate the answer using the information given in the question.

1 pound : 3500 grams

5 pounds : x grams

As it is given that the individual is burning no calories, we do not have to factor in any additional numbers.

<u><em>Method</em><em> </em><em>A</em><em>:</em></u>

To go from 1 in the first ratio to 5 in the second ratio, they multipled 1 by 5. Hence, to go from 3500 in the first ratio to x in the second ratio, we must multiply by 5.

x = 3500 × 5

x = 17500

<em><u>Method B</u>:</em>

To solve for the answer x, we can convert the ratios into fractions.

1 / 5 = 3500 / x

3500 / x = 1 / 5

To make x the subject, multiply the denominator of the left fraction with the numerator of the right fraction and place it on the left side. Then multiply the numerator of the left fraction with the denominator of the right fraction and place it on the right side.

x = 5 × 3500

x = 17500

4 0
3 years ago
A fixed amount of oxygen gas is held in a .500 L tank at a pressure of 4.39 atm. The tank is connected to an empty 1.50 L tank b
DochEvi [55]

Answer:

1.0975 atm.

Explanation:

<em>According to Boyle’s Law:</em> " At constant temperature , the  volume of a given quantity of a gas  varies inversely with its pressure".

P α 1/V.

<em>∴ P₁V₁ = P₂V₂.</em>

P₁ = 4.39 atm, V₁ = 0.5 L.

P₂ = ??? atm, V₂ = 2.0 L.

<em>∴ P₂ = P₁V₁/V₂</em> = (4.39 atm)(0.5 L) / (2.0 L) = <em>1.0975 atm.</em>

5 0
3 years ago
Calculate the mass in grams of each sample.<br> 4.88x10^20 H2O2 molecules
AleksAgata [21]

4.88x10^20 H2O2 molecules

5 0
3 years ago
Can I get some help?
Brut [27]
Yes, of course))))))
6 0
3 years ago
Using the following equation: 3H2SO4+ 2Fe -&gt; Fe2(SO4)3+ 3H2
Mariana [72]

Answer:

H₂SO₄

Explanation:

Given data:

Number of moles of H₂SO₄ = 15 mol

Number of moles of Fe = 13 mol

Which reactant is limiting reactant = ?

Solution:

Chemical equation:

3H₂SO₄  + 2Fe      →          Fe₂(SO₄)₃  + 3H₂

now we will compare the moles reactant with product.

               H₂SO₄         :          Fe₂(SO₄)₃  

                  3               :              1

                 15               :              1/3×15 = 5

                H₂SO₄         :            H₂

                  3               :              3

                 15               :              15

                Fe               :          Fe₂(SO₄)₃  

                  2               :              1

                 13               :              1/2×13 = 6.5

                Fe               :                H₂

                  2               :                 3

                 13               :              3/2×13 = 19.5

Number of moles of product formed by  H₂SO₄ are less thus it will act as limiting reactant.

8 0
3 years ago
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