Taking into account the reaction stoichiometry, 15.33 grams ethanol could be obtained from 30 grams of glucose.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The molar mass of the compounds is:
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
The following rule of three can be applied: if by reaction stoichiometry 180 grams of glucose form 92 grams of ethanol, 30 grams of glucose form how much mass of ethanol?
<u><em>mass of ethanol= 15.33 grams</em></u>
Then, 15.33 grams ethanol could be obtained from 30 grams of glucose.
Learn more about the reaction stoichiometry:
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Answer:
6.9428 kg of CO2
Explanation:
1) Use Avogadro's number that states 1 mole = 6.022 x 10^23 particles. Convert 9.5 x 10^25 molecules into moles.
9.5 x 10^25 CO2 molecules = 157.75 moles CO2
2) Convert 157.75 moles of CO2 into grams. CO2's molar mass is 44.01g.
= 6942.79g
3) Convert 6942.79 grams into kilograms (divide by 1000):
6.9428 kg