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sveticcg [70]
3 years ago
11

Which statement about atoms is not correct

Chemistry
2 answers:
AnnyKZ [126]3 years ago
7 0

Answer:

Atoms are not able to exist independently.

Explanation:

Brainliest pls

MrRissso [65]3 years ago
6 0

Answer:

please provide more info

Explanation:

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Reactivity is an impetus For which a chemical substance undergoes A chemical either by itself or with another materialWith an overall release of energy
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A student determines that she used 0.0665 mol of sodium hydroxide (NaOH) to completely titrate 25.00 mL of sulfuric acid solutio
AysviL [449]

To determine the concentration of one solution which is specifically basic or acidic solution through taking advantage on its points of equivalence, titration analysis is done.

Let us determine the reaction for the titration below:

2NaOH +2H2SO4 = Na2SO4 +2H2O

 

So,

0.0665 mol NaOH (2 mol H2SO4/ 2mol NaOH) / .025 L solution 

= 2.62 M H2SO4


The answer is the fourth option: 

<span>2.62 M</span>
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3 years ago
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What element is primarily used in appliances to make electronic chips
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Answer:

Option A

Explanation:

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A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

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b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
If 5.3 g of gallium reactions with 5.3 g of oxygen according to the following reaction, how many grams of gallium oxide can be p
monitta

Answer:

can you help mine please

How many molecules of chlorine are needed to react with 56.Og of iron to form Iron (III) chloride (FeCl3)?

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