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alukav5142 [94]
2 years ago
9

The isotope \left.\begin{array}{r}212 \\ 83\end{array}\right? Bi has a half-life of 1.01 yr. What mass (in mg) of a 2.00-mg samp

le will remain after 3.75X10³ h?
Chemistry
1 answer:
anyanavicka [17]2 years ago
5 0

Half-life is the length of time it takes for half of the radioactive atoms of a specific radionuclide to decay. A good rule of thumb is that, after seven half-lives, you will have less than one percent of the original amount of radiation.

<h3>What do you mean by half-life?</h3>

half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay (change spontaneously into other nuclear species by emitting particles and energy), or, equivalently, the time interval required for the number of disintegrations per second of a radioactive.

<h3>What affects the half-life of an isotope?</h3>

Since the chemical bonding between atoms involves the deformation of atomic electron wavefunctions, the radioactive half-life of an atom can depend on how it is bonded to other atoms. Simply by changing the neighboring atoms that are bonded to a radioactive isotope, we can change its half-life.

Learn more about half life of an isotope here:

<h3>brainly.com/question/13979590</h3><h3 /><h3>#SPJ4</h3>
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If 3.25 mol of Ar occupies 100. L at a particular temp and pressure, what volume does
gtnhenbr [62]

Answer:

435.38 L

Explanation:

From the question,

Applying ideal gas equation,

PV = nRT................... Equation 1

Where P = Pressure, V = Volume, n = number of moles, R = molar gas constant, T = Temperature.

Since Temperature and Pressure were constant,

V ∝ n

V/n = V'/n'.................... Equation 2

Where V and V'  = the initial and final Volume of Ar respectively, n and n'  = the initial and final moles of Ar respectively

make V' the subject of the equation

V' = Vn'/n............... Equation 3

Given: V = 100 L, n = 3.25 mol, n' = 14.15

Substitute into equation 3

V' = (100×14.14)/3.25

V' = 435.38 L

8 0
3 years ago
How much heat is absorbed by 0.060 kg of copper when it is heated from 20.0°C to 80.0°C if the specific heat of copper is 385J/k
Elina [12.6K]

Answer:

its 1386J

Explanation:

7 0
4 years ago
Ag(s)+CN−(aq)+O2(g)→Ag(CN)−2(aq) Express your answer as a chemical equation. Identify all of the phases in your answer. Express
Lerok [7]

Answer : The balanced redox reaction will be,

4Ag(s)+8CN^-(aq)+O_2(g)+4H^+(aq)\rightarrow 4Ag(CN)_2^-(aq)+2H_2O(l)

Explanation :

The given chemical equation is,

Ag(s)+CN^-(aq)+O_2(g)\rightarrow Ag(CN)_2^-(aq)

In the half reaction method, the number of atoms in each half reaction and number of electrons must be balanced.

The half reactions in the acidic medium are :

Reduction : O_2(g)+4H^+(aq)+4e^-\rightarrow 2H_2O(l)   ......(1)

Oxidation : Ag(s)+2CN^-(aq)\rightarrow Ag(CN)_2^-(aq)+1e^-  .......(2)

Now multiply the equation (2) by 4 and then added both equation, we get the balanced redox reaction.

Thus, the balanced redox reaction will be,

4Ag(s)+8CN^-(aq)+O_2(g)+4H^+(aq)\rightarrow 4Ag(CN)_2^-(aq)+2H_2O(l)

7 0
4 years ago
Consider the reaction below. Mg(s) + 2HCl(aq) mc019-1.jpg H2(g) + MgCl2(aq) What is the most likely effect of an increase in pre
bonufazy [111]
1) Reaction:

Mg(s) + 2HCl (aq) ----> H2(g) + MgCl2(aq)

2) Analysis

An increase in pressure affects directly the rate of reaction involving reactiong gases. Changing the pressure where there are only solids or liquids does not affect the rate of reaction.

This reaction is not an equilibrium, the reaction is only forward. So, the reacting components, Mg(s) and HCl(aq) are a solid and a liquid.

Therefore, the reaction is not affected by the change in pressure.

Answer: the reaction is not affected at all.


4 0
4 years ago
Read 2 more answers
Blood clotting factors are regulated by allosterie control.(T/F)
weeeeeb [17]

Answer:

I think false idk if this is right

6 0
3 years ago
Read 2 more answers
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