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alukav5142 [94]
1 year ago
9

The isotope \left.\begin{array}{r}212 \\ 83\end{array}\right? Bi has a half-life of 1.01 yr. What mass (in mg) of a 2.00-mg samp

le will remain after 3.75X10³ h?
Chemistry
1 answer:
anyanavicka [17]1 year ago
5 0

Half-life is the length of time it takes for half of the radioactive atoms of a specific radionuclide to decay. A good rule of thumb is that, after seven half-lives, you will have less than one percent of the original amount of radiation.

<h3>What do you mean by half-life?</h3>

half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay (change spontaneously into other nuclear species by emitting particles and energy), or, equivalently, the time interval required for the number of disintegrations per second of a radioactive.

<h3>What affects the half-life of an isotope?</h3>

Since the chemical bonding between atoms involves the deformation of atomic electron wavefunctions, the radioactive half-life of an atom can depend on how it is bonded to other atoms. Simply by changing the neighboring atoms that are bonded to a radioactive isotope, we can change its half-life.

Learn more about half life of an isotope here:

<h3>brainly.com/question/13979590</h3><h3 /><h3>#SPJ4</h3>
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When 25.0 grams of solid potassium hydroxide (KOH, molar mass = 56.1 g/mol) is dissolved in 100.0 grams of water, the solution i
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Answer:

They gave you the equation; Cp=,

just plug everything in! You’ve seen this; I have long ago, but we had different units. Sorry, but it’s right there! Go get it!

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3 years ago
If 30 ml of water containing 15 mg of salicylate is extracted with 30 ml of chloroform, 2.59 mg of salicylate remains in the wat
In-s [12.5K]

Answer:

Distribution coefficient: 4.79

Explanation:

Distribution coefficient is the ratio between equilibrium concentration of non-aqueous phase and aqueous phase where both solvents are inmiscible. The equation for the problem is:

Distribution coefficient: Concentration in chloroform / Concentration in Water

<em>Concentration in water: 2.59mg / 30mL = 0.08633mg/mL</em>

<em>Concentration in chloroform: (15mg-2.59mg) / 30mL = 0.4137mg/mL</em>

<em />

Distribution coefficient: 0.4137mg/mL / 0.08633mg/mL

<h3>Distribution coefficient: 4.79</h3>
8 0
2 years ago
The chart below shows examples of solids, liquids, gases, and plasma.
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4 0
2 years ago
Read 2 more answers
Can someone help me solve this please 2.150 x 10 ^-12 dm / 5.02 x 10 ^-5dm^3
zavuch27 [327]

4.3 x 10⁻⁸dm⁻²

Explanation:

Problem:

                   \frac{2.150 x 10^{-12} dm }{5.02  x 10 ^{-5} dm^{3} }

 To solve this problem, we have apply the right rule of indices operation.

If we have an indices in the form;

 \frac{a^{n} }{b^{k} } = (\frac{a }{b } )^{n-k}

  Solving this problem:

   = \frac{2.15}{5.02}   x  10^{-12 -(-5})

   = 0.43 x 10⁻⁷

   = 4.3  x 10⁻¹ x 10⁻⁷

   = 4.3 x 10⁻⁸

for the units:

 \frac{dm}{dm^{3} }   = \frac{dm}{ dm x dm x dm} = \frac{1}{dm^{2} }  = dm^{-2}

  The solution is:  4.3 x 10⁻⁸dm⁻²

   

learn more:

long division brainly.com/question/1747117

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4 0
3 years ago
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