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alukav5142 [94]
1 year ago
9

The isotope \left.\begin{array}{r}212 \\ 83\end{array}\right? Bi has a half-life of 1.01 yr. What mass (in mg) of a 2.00-mg samp

le will remain after 3.75X10³ h?
Chemistry
1 answer:
anyanavicka [17]1 year ago
5 0

Half-life is the length of time it takes for half of the radioactive atoms of a specific radionuclide to decay. A good rule of thumb is that, after seven half-lives, you will have less than one percent of the original amount of radiation.

<h3>What do you mean by half-life?</h3>

half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay (change spontaneously into other nuclear species by emitting particles and energy), or, equivalently, the time interval required for the number of disintegrations per second of a radioactive.

<h3>What affects the half-life of an isotope?</h3>

Since the chemical bonding between atoms involves the deformation of atomic electron wavefunctions, the radioactive half-life of an atom can depend on how it is bonded to other atoms. Simply by changing the neighboring atoms that are bonded to a radioactive isotope, we can change its half-life.

Learn more about half life of an isotope here:

<h3>brainly.com/question/13979590</h3><h3 /><h3>#SPJ4</h3>
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When 91.5 g of isopropyl alcohol which has an empirical formula of C3H8O is burned in excess oxygen gas, how many grams of H2O a
Kobotan [32]

Answer:

109.7178g of H2O

Explanation:

First let us generate a balanced equation for the reaction. This is illustrated below:

2C3H8O + 9O2 —> 6CO2 + 8H2O

Next we will calculate the molar mass and masses of C3H8O and H20. This is illustrated below:

Molar Mass of C3H8O = (3x12.011) + (8x1.00794) + 15.9994 = 36.033 + 8.06352 + 15.9994 = 60.09592g/mol.

Mass of C3H8O from the balanced equation = 2 x 60.09592 = 120.19184g

Molar Mass of H2O = (2x1.00794) + 15.9994 = 2.01588 + 15.9994 = 18.01528g/mol

Mass of H2O from the balanced equation = 8 x 18.01528 = 144.12224g

From the equation,

120.19184g of C3H8O produced 144.12224g of H20.

Therefore, 91.5g of C3H8O will produce = (91.5 x 144.12224) /120.19184 = 109.7178g of H2O

7 0
3 years ago
The particles of a gas are<br> O electrons<br> O atoms or molecules<br> O neutrons<br> O waves
Harrizon [31]
Answer:
atoms or molecules

Explanation:
Gas particles are constantly bumping into each other and the borders of their container.

8 0
2 years ago
The dissociation of a/an ________ releases hydrogen ions and increases the concentration of hydrogen ions in a solution.
Crank
Acid...hope it helps
5 0
3 years ago
1. A given mass of air has a volume of 6.00 L at 80.0°C. At constant pressure, the temperature is
earnstyle [38]

3 L will be the final volume for the gas as per Charle's law.

Answer:

Explanation:

The kinetic theory of gases has two significant law which forms the backdrop of motion of gases. They are Charle's law and Boyle's law. As per Charle's law, the volume of any gas molecule at constant pressure is directly proportional to the temperature of the molecule.

V∝ T

Since, here two volumes are given and at two different temperatures with constant pressure. Then as per Charle's law, the relation between the volumes of air at different temperature will be

\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }

So in this case, V1 = 6 L and T1 = 80° C. Similarly, T2 = 40° C. So we have to determine the V2.

\frac{6}{80}=\frac{V_{2} }{40}

V_{2}=\frac{6*40}{80}=3 L

So, 3 L will be the final volume for the gas as per Charle's law.

4 0
3 years ago
Which of the following is a pure substance? A. Air B. carbon dioxide C. soda D. salt water
uysha [10]
B- Carbon dioxide, every other option listed is composed of more than one thing.
4 0
3 years ago
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