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Alona [7]
2 years ago
15

What is the change in oxidation number of bromine in the following re-dox reaction Cl 2 +2HBr 2HCl+Br 2 A -2;0 B) -1;0 C) 0: -1

D) 0;-2
Chemistry
1 answer:
ch4aika [34]2 years ago
6 0

Answer:

ANSWER

ANSWER: +1

EXPLANATION

What is the change in oxidation number of bromine in the following re-dox reaction Cl 2 +2HBr 2HCl+Br 2 A -2;0 B) -1;0 C) 0: -1 D) 0;-2

for Cl 2 +2HBr 2HCl+Br 2 , the Cl in Cl2 is reduced from "0" to

"-1" and the Br in HBr is oxidized from "-1" to "0"

So the change in oxidation number is +1

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Show work, thanks
GarryVolchara [31]

Answer:

Q.1

Given-

Volume of solution-1 L

Molarity of solution -6M

to find gms of AgNO3-?

Molarity = number of moles of solute/volume of solution in litre

number of moles of solute = 6×1= 6moles

one moles of AgNO3 weighs 169.87 g

so mass of 6 moles of AgNO3 = 169.87×6=1019.22

so you need 1019.22 g of AgNO3 to make 1.0 L of a 6.0 M solution

7 0
3 years ago
1. Describe the evidence that stress plays a role in the development of schizophrenia.
valentina_108 [34]

Answer:

Research shows that patients with schizophrenia are more affected by stress physically as well as emotionally, for instance they show different changes in heart rate under stress and a greater overall risk of cardiovascular disease.

Explanation:

8 0
3 years ago
What is the empirical formula of propene CH3 CH2 CH2​
kiruha [24]

Answer:

<u>CH</u>

Explanation:

Molecular formula of propene : <u>C₃H₆</u>

Take the HCF of carbon and hydrogen atoms :

  • 3 = 3
  • 6 = 2 x 3

Then, we can write the formula as :

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Empirical Formula :

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<u></u>

The empirical formula of propene is <u>CH</u>

6 0
2 years ago
Please i need help ……
nasty-shy [4]

Answer:

H2

Explanation:

(l) means liquid

(s) means solid

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I hope this helped [:

3 0
2 years ago
How many grams of water are required to produce 5.50L of hydrogen gas at 25.0 degrees C and 755mmHg?
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Answer is: 4.02 grams of water are required.
Chemical reaction: BaH₂ + 2H₂O → Ba(OH)₂ + 2H₂.
Ideal gas law: p·V = n·R·T.
p = 755 mm Hg ÷ 760.0 mmHg / atm = 0.993 atm.
T = 25 + 273.15 = 298.15 K.
V(H₂) = 5.50 L.
R = 0,08206 L·atm/mol·K.
n(H₂) = 0.993 atm · 5.5 L ÷ 0,08206 L·atm/mol·K · 298.15 K.
n(H₂) = 0.223 mol.
From chemical reaction: n(H₂O) : n(H₂) = 1 : 1.
n(H₂O) = 0.223 mol.
m(H₂O) = 0.223 mol · 18 g/mol.
m(H₂O) = 4.02 g.
3 0
3 years ago
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