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Alona [7]
2 years ago
15

What is the change in oxidation number of bromine in the following re-dox reaction Cl 2 +2HBr 2HCl+Br 2 A -2;0 B) -1;0 C) 0: -1

D) 0;-2
Chemistry
1 answer:
ch4aika [34]2 years ago
6 0

Answer:

ANSWER

ANSWER: +1

EXPLANATION

What is the change in oxidation number of bromine in the following re-dox reaction Cl 2 +2HBr 2HCl+Br 2 A -2;0 B) -1;0 C) 0: -1 D) 0;-2

for Cl 2 +2HBr 2HCl+Br 2 , the Cl in Cl2 is reduced from "0" to

"-1" and the Br in HBr is oxidized from "-1" to "0"

So the change in oxidation number is +1

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klasskru [66]

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B. %yield = 75%

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A. From the equation,

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Hello there!

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I hope this helps!
Brady

5 0
3 years ago
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