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svp [43]
3 years ago
6

Convert 77 centimeters into feet. Hint: 1 in = 2.54 cm; 1 ft = 12 in​

Mathematics
1 answer:
Over [174]3 years ago
8 0

Answer:

77 centimeters = 2.52625 feet

Step-by-step explanation:

Hope this helps!      :3

plz mark as brainliest!

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Y = 3

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Evaluate the expression 3.14(a2 + ab) when a = 3 and b = 4. (Input decimals only, such as 12.71, as the answer.)
Rama09 [41]
A= 3
b= 4

=3.14(a^2 + ab)
substitute the given a & b values in expression

=3.14((3)^2 + (3*4))
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3 years ago
Geometry help!!
Eduardwww [97]
It would be A, Side Angle Side (SAS).  Because you are given we congruent sides, and tow right angles.  Using the reasoning of "If two two angles are both right angles then they are congruent" you can prove the angles congruent. 

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3 0
3 years ago
What is the correct answer
blagie [28]

Answer:

i think 3rd

Step-by-step explanation:

6 0
3 years ago
4. A company manufactures tires to meet the annual demand of 125,000 production runs. One production run involves producing 100
lyudmila [28]

Answer:

a) Economic order or production quantity = 2,500 tires.

Number of production runs in a year = 50 runs

Hence, 2,500 tires should be produced in each of the 50 runs in a year to minimize total cost.

b) Minimum total inventory cost = Tsh 30,000

Step-by-step explanation:

The total cost for the tire production firm will be a sum of the total production cost and total inventory cost.

Total cost = Total Production cost + Total inventory cost

Total Production Cost = (Number of production runs in a year) × (Setup Cost of one production run)

Number of production runs in a year = (Annual demand)/(Number of units produced per production run)

Let the annual demand = D

Number of units produced per production run = Q

Setup Cost of one production run = S

Number of production runs in a year = (D/Q)

Total Production Cost = (DS/Q)

Total inventory Cost = (Average inventory level) × (Cost of holding 1 unit in inventory)

Average inventory level is usually assumed to be half of the number of units in a production run = (Q/2)

Cost of Holding a unit of product in inventory = H

Total inventory Cost = (QH/2)

Total cost = TC = (DS/Q) + (QH/2)

At minimum cost, (dTC/dQ) = 0

(dTC/dQ) = -(DS/Q²) + (H/2) = 0

(DS/Q²) = (H/2)

Q² = (2DS/H)

Hence,

Economic order/production quantity = Q = √(2DS/H)

For this question

D = Annual demand = 125,000 tires

S = Setup cost for one production run = Tsh 600

H = Holding cost for one unit in inventory = Tsh 24

Q = √(2×125000×600/24) = 2,500 units

Number of production runs in a year = (D/Q) = (125000/2500) = 50 production runs.

b) Total Inventory Cost = (QH/2)

At minimum total inventory cost, Q = 2,500

Minimum total inventory cost = (2500×24/2) = Tsh 30,000

Hope this Helps!!!

4 0
3 years ago
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