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liubo4ka [24]
3 years ago
15

8. How many moles of carbon dioxide are there in 52.06 g of carbon dioxide?

Chemistry
2 answers:
Lelechka [254]3 years ago
5 0

Answer:

B) 1.183

Explanation:

To convert from grams (mass) to moles, we need to divide by the atomic mass (amu)..

The amu of CO_{2}  is 44.008

52.06/44.08 = 1.182966733

This can be rounded to 1.1830 moles of CO2

Blababa [14]3 years ago
3 0
Your answer is B !! 1.183 moles of carbon dioxide are in 52.06 g of carbon dioxide.


Can you please mark me BRAINLEST?
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Answer:

  • <em>Option D. temperature</em>

Explanation:

Indeed it is generally established that <em>temperature is a measure of the kinetic energy ot the particles</em>.

The <em>kinetic energy</em> of a particle is proportional to the product of the mass and the square of the speed. Mathematically, the kinetic energy, KE, is:

  • KE = (1/2) m × v²

Where m is the mass and v the speed of the particle.

In a sample of matter, not all the particles have the same speed, hence not all the particles have the same kinetic energy.

The kinetic energy and the temperature are related by the Boltzman equation:

  • KE = (3/2)KT

Where K is a constant (Boltzman constant) and T is the absolute temperature.

Therefore, as you can see from the last equation, <em>the temperaure is a measure of the averate kinetic energy of the particles in a sample of matter</em>.

This is, at a certain temperature, every substance has the same average kinetic energy.

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3 years ago
In the reaction of magnesium with oxygen, explain which atom is the reducing agent.
Mnenie [13.5K]

Answer:

Mg.

Explanation:

  • The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
  • An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. Also known as the electron acceptor, the oxidizing agent is normally in one of its higher possible oxidation states because it will gain electrons and be reduced.
  • A reducing agent (also called a reductant or reducer) is an element (such as calcium) or compound that loses (or "donates") an electron to another chemical species in a redox chemical reaction.
  • For the reaction:

<em>Mg + 1/2O₂ → MgO.</em>

<em></em>

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3 years ago
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5095

Explanation:

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2 years ago
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150 mL of 0.25 mol/L magnesium chloride solution and 150 mL of 0.35 mol/L silver nitrate solution are mixed together. After reac
Murljashka [212]

Answer:

0.175\; \rm mol \cdot L^{-1}.

Explanation:

Magnesium chloride and silver nitrate reacts at a 2:1 ratio:

\rm MgCl_2\, (aq) + 2\, AgNO_3\, (aq) \to Mg(NO_3)_2 \, (aq) + 2\, AgCl\, (s).

In reality, the nitrate ion from silver nitrate did not take part in this reaction at all. Consider the ionic equation for this very reaction:

\begin{aligned}& \rm Mg^{2+} + 2\, Cl^{-} + 2\, Ag^{+} + 2\, {NO_3}^{-} \\&\to  \rm Mg^{2+} + 2\, {NO_3}^{-} + 2\, AgCl\, (s)\end{aligned}.

The precipitate silver chloride \rm AgCl is insoluble in water and barely ionizes. Hence, \rm AgCl\! isn't rewritten as ions.

Net ionic equation:

\begin{aligned}& \rm Ag^{+} + Cl^{-} \to AgCl\, (s)\end{aligned}.

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\begin{aligned}n(\text{initial}) &= c(\text{initial}) \cdot V(\text{initial}) \\ &= 0.25\; \rm mol \cdot L^{-1} \times 0.150\; \rm L \\ &= 0.0375\; \rm mol \end{aligned}.

Since nitrate ions \rm {NO_3}^{-} do not take part in any reaction in this mixture, the quantity of this ion would stay the same.

n(\text{final}) = n(\text{initial}) = 0.0375\; \rm mol.

However, the volume of the new solution is twice that of the original nitrate solution. Hence, the concentration of nitrate ions in the new solution would be (1/2) of the concentration in the original solution.

\begin{aligned} c(\text{final}) &= \frac{n(\text{final})}{V(\text{final})} \\ &= \frac{0.0375\; \rm mol}{0.300\; \rm L} = 0.175\; \rm mol \cdot L^{-1}\end{aligned}.

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