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lilavasa [31]
3 years ago
6

(a) What is the escape speed on a spherical asteroid whose radius is 301 km and whose gravitational acceleration at the surface

is 0.412 m/s2
Physics
1 answer:
Allushta [10]3 years ago
7 0

Answer:

V.E=498.02m/s^2

Explanation:

From the question we are told that:

Radius r=301Km

Gravitational acceleration g=0.412 m/s^2

Generally the equation for Escape velocity is mathematically given by

 V.E^2=2gr

 V.E^2=2*0.412m/s^2*301000

 V.E^2=248024

 V.E=\sqrt{248024}

 V.E=498.02m/s^2

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Explanation:

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5 0
3 years ago
A 120-g block of copper is taken from a kiln and quickly placed into a beaker of negligible heat capacity containing 300 g of wa
gavmur [86]

Answer : The correct option is, (d) 535^oC

Explanation :

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c_2 = specific heat of water = 1.00cal/g^oC

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m_2 = mass of water = 300 g

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Now put all the given values in the above formula, we get:

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7 0
4 years ago
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