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erastova [34]
3 years ago
7

If a rock has a weight of 30 N on Earth, would its weight be more or less if it was on Jupiter (gravity on Jupiter = 25 m/s2)?

Physics
1 answer:
goldenfox [79]3 years ago
8 0
I’m sorry this is not going as planned
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Use the dimensional analysis and check the correctness of given equation:- PV= nRT (no spam ) plz
gayaneshka [121]

Answer:

PV = nRT

n and R are constants.

Dimensions of Pressure = ML^-1T^-1

Volume dimensions = L³

(pressure)(volume) = (temperature) \\ (ML {}^{ - 1} T {}^{ - 2} )(L {}^{3} ) = (k) \\ ML {}^{2} T {}^{ - 2}  = k

It is dimensionally inconsistent or incorrect

7 0
2 years ago
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Me kitten runs 40 meters in 8 seconds what is his speed?
AfilCa [17]
The answer is five because if you do 8×n=40 and if you count by five you would get the answer is 5
3 0
3 years ago
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Find the ratio of the radii of a baseball to the Earth, knowing that the radius of a baseball is .09 m, and that the Earth's rad
Xelga [282]
0.09 / 6.37 x 10⁶ = 1.4129 x 10⁻⁸

The radius of the baseball is  1.4129 x 10⁻⁸   the radius of the Earth.
6 0
2 years ago
While riding in a moving car, you toss an egg directly upward. Does the egg tend to land behind you, in front of you, or back in
bazaltina [42]

Answer:

Explanation:

The movement of a body can be analyzed using New's first law. In an inertial frame (without acceleration) every body is kept at rest or moving at constant speed until there is an external force that changes this state

Let's analyze these cases in the framework of this first law

a) If the vehicle is going at constant speed the two bodies (the egg and the hands) do not change movement so he had returned to the hands

b) If the vehicle accelerates the passenger goes faster, but the egg that is not subject to anything does not change the movement, so it falls behind the passenger

c) If the vehicle slows down, the passenger reduces its speed and the distance traveled in time, but the egg that is not attached follows its movement and falls in front of the passenger.

4 0
3 years ago
A ship sets sail from Rotterdam, The Netherlands, intending to head due north at 6.5 m/s relative to the water. However, the loc
sattari [20]

Answer:

Explanation:

velocity of ship with respect to water = 6.5 m/s due north

\overrightarrow{v}_{s,w}=6.5 \widehat{j}

velocity of water with respect to earth = 1.5 m/s at 40° north of east

\overrightarrow{v}_{w,e}=1.5\left ( Cos40\widehat{i} +Sin40\widehat{j}\right)

velocity of ship with respect to water = velocity of ship with respect to earth - velocity of water with respect to earth

\overrightarrow{v}_{s,w} = \overrightarrow{v}_{s,e} - \overrightarrow{v}_{w,e}

\overrightarrow{v}_{s,e} = 6.5 \widehat{j}- 1.5\left (Cos40\widehat{i} +Sin40\widehat{j}  \right )

\overrightarrow{v}_{s,e} = - 1.15 \widehat{i}+5.54\widehat{j}

The magnitude of the velocity of ship relative to earth is \sqrt{1.15^{2}+5.54^{2}} = 5.66 m/s

5 0
3 years ago
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