How does a graph with no trend differ from a graph with anomalous data points?
2 answers:
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So let's use some equations to represent the data [let R= cost of ring & B= cost of bracelet]
R= B + $ 36 .... (1)
B=
× R ... (2)
By using simultaneous equations to solve for B and R.
Substitute eq. (1) into eq. (2)
B = × (B + $36)
B =B + 
⇒ B = $48
By substituting value of B into ea (1)
If R = B + $36
R = ($48) + $36
= $84
∴ <span> the total of the two items = R + B
= $84 + $48
</span> = $132
R= B + $ 36 .... (1)
B=
By using simultaneous equations to solve for B and R.
Substitute eq. (1) into eq. (2)
B =
B =
⇒ B = $48
By substituting value of B into ea (1)
If R = B + $36
R = ($48) + $36
= $84
∴ <span> the total of the two items = R + B
= $84 + $48
</span> = $132
Answer:
B) 1.65
Explanation:
See the image uploaded for the percent error formula
Work:
Theoretical Value - Accepted Value/Accepted Value * 100
= (24.7-24.3)/24.3 * 100
= 0.4/24.3 * 100
= 0.0164609053 * 100
= 1.64609053
Can be rounded to 1.65%
