G measures 117, angle c measures 22, and angle e measures 40. Angle f
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The rate of change of temperature with time at a point in time is given by
the derivative of the function for the temperature of the soup.
The correct responses are;
- a) H'(5) is approximately<u> -2.6 degrees Celsius per minute</u>.
- b) Yes
- c) The equation for the line tangent is<u> y = -3.6·t + 90.8</u>
- The approximate value of C(5) is <u>72.8 °C</u>
- d) The rate of change of the temperature of the soup at t = 3 minutes is <u>-3.6 degrees Celsius per minute</u>.
Reasons:
a) From the data in the table, we have;
The approximate value of H'(5) is given by the average value of the rate of
change of the temperature with time between points, t = 3, and t = 8
Therefore;
Which gives;
Therefore, H'(5) = <u>-2.6°C per minute</u>
b) Given that the function is twice differentiable over the interval, 0 ≤ t ≤ 12, the function for the change in temperature is continuous in the interval 0 ≤ t ≤ 12
At t = 0, H(0) = 90 °C
At t = 12, H(12) = 58 °C
- 58 °C < 60 < 90 °C
Therefore, there exist a temperature, of 60 °C between 90° C and 58 °C
c) The given derivative of <em>C</em> is,
At t = 3, we have;
Therefore, we have;
y - 80 ≈ -3.1 × (x - 3)
The equation for the tangent is; y = -3.6 × (x - 3) + 80
y = -3.6·x + 10.8 + 80 = -3.6·x + 90.8
- The equation for the tangent is; <u>y = -3.6·x + 90.8</u>
The value of C(5) is approximately, C(5) ≈ -3.6 × 5 + 90.8 = 72.8
- <u>C(5) ≈ 72.8°</u>
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d) Based on the the model above, the rate at which the temperature of the
soup is changing at t = 3 minutes is <u>-3.6 degrees per minute</u>.
Learn more about calculus and concepts here:
Answer:
(a) 7.5 seconds
(b) The horizontal distance the package travel during its descent is 1737.8 ft
Step-by-step explanation:
(a) The given function for the height of the object is s = -16·t² + v₀·t + s₀
The initial height of the object s₀ = 900 feet
The initial vertical velocity of the object v₀ = 0 m/s
The time it takes the package to strike the ground is found as follows;
0 = -16·t² + 0×t + 900
900 = 16·t²
t² = 900/16 = 62.25
t = √62.25 = 7.5 seconds
(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have
158 miles/hour = 231.7126 ft/s
The horizontal distance the package covers in the 7.5 second of vertical flight = 231.7126 ft/s × 7.5 s = 1737.8445 feet = 1737.8 ft to one decimal place
The horizontal distance the package travel during its descent = 1737.8 ft.
Answer:
C.
Step-by-step explanation:
To find the slope when you know two points, use this formula:
M = y₂ - y₁ ÷ x₂ - x₁
M = (4 - (-8)) ÷ (0 - (-7))
M = 12 ÷ 7
M =
Hope that helps.