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3 years ago

NEED HELP ASAP!! Solve for m

Mathematics

1 answer:

kirill115 [55]3 years ago

4 0

Angle B = 56.309932474020215

This is through using a trigonometry calculator I forgot how to set it up tbh.

Hope this helps ;)

For extra info Angle C = 33.690067525979785.

They add up to 90 which added with the right angle of 90 means the interior angles add to 180 meaning it is in fact correct because a triangle is always 180 inside.

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PLEASE HELP !!!!!<br> What is the value of the missing angle?

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Step-by-step explanation:

180 - 100 = 80

80 = 30 = 110

180 - 110 = 70

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How do you find a vector that is orthogonal to 5i + 12j ?

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$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
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\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

3 years ago

Can someone help? pls i really need it right now

taurus [48]

A linear function is a function that has constant average rate of change;

Also, a relation that represents a function must have unique input and output values.

<h3>Question 11: Relations and Functions</h3>

A relation may or may not represent a function.

When the domain and the range of a relation are unique, then the relation is a function.

So, the true option is (b) function

<h3>Question 12: Relations and Functions</h3>

A one-to-many relation is not a function.

This is so because the domain and the range of the function are not unique

So, the true option is (c) figure 3: one-to-many.

<h3>Question 13: Variables</h3>

A dependent variable is a variable that depends on other variables for its value.

In this case, the dependent variable is (b) boosts the immune system.

<h3>Question 14 and 15: Domain and Range</h3>

The domain is the set of input values (i.e. the x values), while the range is the set of output values (i.e. the y values)

This means that:

The domain of the function is: (a) {2,3,4,5,6}
The range of the function is: (b) {4,6,8,10,12}

<h3>Question 16 and 17: Linear functions</h3>

The graph of a linear function is represented by a straight line, and it has a constant slope or rate.

This means that:

Graph C is a linear function
Table B is a linear function

<h3>Question 18: The table</h3>

The fare of 3 km and 5 km are given as 35 pesos and 55 pesos, respectively.

This means that:

Table (b) represents the information

<h3>Question 19: The linear equation</h3>

Start by calculating the slope (m) using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$m = \frac{55-35}{5-3}$

$m = \frac{20}{2}$

$m = 10\\
$

The linear equation is then calculated as:

$y = m(x -x_1) + y_1$

This gives

$y = 10(x -3) + 35$

$y = 10x -30 + 35$

$y = 10x +5$

This means that:

The linear equation that describes the relationship is (c) $


$ $


$ $y = 10x +5$ ; $x \ge 2$

<h3>Question 20: The fare when the distance is 4km</h3>

This means that x = 4.

So, we have:

$y = 10 \times 4 +5$

$y = 45$

Hence, the fare will be (a) 45 pesos

Read more about linear functions at:

brainly.com/question/15602982

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2 years ago