For the equation F(x) = ax² + bx + c we have:
- maximum value if a<0
- minimum value if a>0
F(x) = -3x² + 18x + 3 ⇒ a = -3, b = 18
a < 0 ⇒ the function has a maximum value
Quadratic function has the maximum value (or minimum) at vertex of its parabola.
The maximum value is k at x=h where:
and k = F(h)

Therefore:
<h3>
The function has a maximum value of 30 at x = 3</h3>
Answer:
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Step-by-step explanation:
We are given these three people age below:
- Jim's age
- Carla's age
- Tomy's age
We define the age of Jim as any variable, because the problem doesn't give any specific age. I will define Jim's age as x.
Next, Carla is 5 years older than Jim. That means if Carla is 5 years older, her age would be x+5.
Then Tomy is 6 years older than Carla. That means the age would be 6+(x+5).
The sum of their three ages is 31 years old. That means we add all these ages and equal to 31.

Combine like terms and solve for x.

Then we substitute the value of x in ages to find these three people ages.
- Jim's age = x = 5
- Carla's age = x+5 = 5+5 = 10
- Tomy's age = 6+(x+5) = 6+(5+5) = 6+10 = 16.
Answer
- Jim's age = 5
- Carla's age = 10
- Tomy's age = 16
To find the price of the stock after 12 weeks, you would have to plug in 12 to x
That would make your equation: y = -0.91(12) + 103.47
Then, you solve:
-0.91(12) would be -10.12
Your equation will now look like this:
y = - 10.12 + 103.47
Then you add -10.12 to 103.47
-10.12 + 103.47 = 92.55
y = 92.55
After 12 weeks, the price of the stocks would be $92.55