Tn=n^2+bn+c. Find the values of b and c if the sequences starts with - 1,2,7,14,..
1 answer:
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Step-by-step explanation:
because
√(11)²+9²=√202=14,2
Answer:
Step-by-step explanation:
Here it is given that a line c has a equation of ,
And there is another line d which is parallel to line c and passes through the point (-4,-4) . And we need to find out the equation of the line .
Firstly we know that the slope of two parallel lines is same . So on comparing the given line to the slope intercept form of the line which is y = mx + c , we have ;
Therefore the slope of the parallel line will be ,
On using the point slope form of the line , we have ;
Substitute the values ,
Simplify ,
Open the brackets ,
Subtract 4/on both sides ,
Simplify ,
<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>l</u><u>i</u><u>n</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>5</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u><u>6</u><u> </u>
Answer:
Perimeter of the quadrilateral PQRS is 25 units
Step-by-step explanation:
From the figure attached,
PQ is a tangent to the given circle so m∠PQR = 90°
Now we apply Pythagoras theorem in the ΔPQR,
PR² = PQ² + QR²
(PT + TR)²= PQ² + 5²
(4 + 5)² = PQ² + 25
81 = PQ² + 25
PQ = √(81 - 25)
= √56
≈ 7.5 units
PQ ≅ PS ≅ 7.5 units
[Since measures of tangents drawn from a point to a circle are always equal]
Perimeter of PQRS = PQ + QR + RS + PS
= 7.5 + 5 + 5 + 7.5
= 25 units
Therefore, perimeter of the quadrilateral PQRS is 25 units.
