Answer:
9+11s
Step-by-step explanation:
9+18s-7s
=9+11s
You can't add 9 and 11s because they are different variables
8, 15, 20, 23, 29, 25, 30, 24, 28, 35, 32, 28, 27, 27, 25, 28, 29, 14, 22, 18 what is the outlier?
Dominik [7]
Answer:
17
Step-by-step explanation:
1. Make an equation.
Moving company #1: y = 17x + 840
Moving company #2: y = 22x + 760
2. Put the equations together and solve
17x + 840 = 22x + 760
-17x -17x
840 = 5x + 760
-760 -760
80 = 5x
5 5
16 = x
When a job is 16 hours they both charge the same thing.
Lim x→0 (√(ax+b)-2)/x=1
You want to know the value of "a" and "b"
lim x→0 (√(ax+b)-2)/x=(√(0+b)-2)/0=(√b -2)/0;
Then if (√b -2)/0=1; the numerator must be "0"
(√b-2)=0
√b=2
(√b)²=2²
b=4
It is necessary the numerator must be "0", if the denominator is "0" and the result is equal a number.
Therefore:
lim (√(ax+4)-2)/x=1
x⇒0
I imagine you know Taylor Series.
√(ax+4)=(4(1+ax/4))¹/²=2(1+ax/4)¹/²
Remember:
(1/2)
(1+x)ᵃ=<span>Σ ( a ) x^a
</span>
In our case:
(1/2) (1/2) (1/2)
(1+ax/4)¹/²=( 0) (ax/4)⁰+( 1 ) (ax/4)¹+( 2) (ax/4)²+...
=1 +(1/2) ax/4 + -1/8 (ax/4)²+...
=1+ax/8-a²x²/128+...
Therefore:
lim (√(ax+4)-2)/x=lim [2(1+ax/8-a²x²/128+...)-2]/x=
x⇒0 x⇒0
lim [(2+ax/4-a²x²/64+...)-2]/x=
x⇒0
lim (ax/4-a²x²/64+...)/x=
x⇒0
lim x(a/4-a²x/64+...)/x=
x⇒0
lim (a/4-a²x/64+...)=(a/4-0-0-0-...)=4/a
x⇒0
Because:
lim (√(ax+4)-2)/x=1
x⇒0
Then:
4/a=1 ⇒ a=4
Answer: a=4; b=4
Answer:
5 pages
Step-by-step explanation:
10% of 50 is 5
(50 divided by 10 = 5)
