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3 years ago

Find the value of 2.8 + 6.5

Mathematics

2 answers:

max2010maxim [7]3 years ago

8 0

Answer:

Step-by-step explanation:

2.8 + 6.5 = 9.3

KatRina [158]3 years ago

6 0

Answer:

9.3

Step-by-step explanation:

2.8+6.5=9.3

You'd use addition to solve this

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In 1985, there were 285 cell phone subscribers in Arlington. The number of subscribers increased by 75% per year since 1985. Fin

ANTONII [103]

Answer:

The number of subscribers in 2008 is 110,845,988

Step-by-step explanation:

The number of cell phone subscribers in Arlington, in t years after 1985, can be modeled by the following equation.

$N(t) = N(0)(1+r)^{t}$

And which N(0) is the number of subscribers in 1985 and r is the rate it increases per year, as a decimal.

In 1985, there were 285 cell phone subscribers in Arlington.

This means that $N(0) = 285$

The number of subscribers increased by 75% per year since 1985.

This means that $r = 0.75$

$N(t) = 285(1.75)^{t}$

Find the number of subscribers in 2008.

2008 is 2008-1985 = 23 years after 1985. So we have to find N(23).

$N(23) = 285(1.75)^{23} = 110,845,988$

The number of subscribers in 2008 is 110,845,988

8 0

3 years ago

While in the water, Meg saw some treasures located

Tema [17]

Answer:

A and D

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Help please and Explain properly with the terms: Corresponding angles and Parallel lines cut by a transversal and AA Criterion

yuradex [85]

Answer: are u still on it?

Step-by-step explanation:

5 0

3 years ago

HELP

Bas_tet [7]

Answer:

328 and the last one is 260

Step-by-step explanation:

i just did the question :p

6 0

3 years ago

Can someone please help me with this again? 5-7<br><br>Thank you so much!

SIZIF [17.4K]

Hi there!

Use the property:

$\frac{x^a}{x^b} = x^{a - b}$
Now, solve by variable.

$\frac{x^2}{x} = x^{2 - 1} = x\\\\\frac{y^5}{y^4} = y^{5 - 4} = y$

Rewrite:
$= x * y * z^3 = \boxed{\text{ D. } xyz^3}}$

Solve the inside of the parenthesis, and each term separately.

Use the property:
$x^0 = 1$

$(7 + 3^2)^0 = 1 \\\\(8^0 + 3)^2 = (1 + 3)^2 = 4^2 = 16\\\\1 + 16 = \boxed{ \text{ C. } 17}$

Solve like above:
$(4 + 2^2)^0 = 1\\\\(7^0 + 4)^{-3} = (1 + 4)^{-3} = 5^{-3}$

The negative exponent indicates taking the reciprocal. Using the property:
$x^{-a} = \frac{1}{x^a}$

Therefore:
$5^{-3} = \frac{1}{5^3} = \boxed{ \text{ D. }\frac{1}{125}}$

4 0

2 years ago