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yuradex [85]
3 years ago
15

Avery is buying string and beads to make bracelets for her family and friends. She plans to divide the string into 9-inch pieces

to make at least 27 bracelets. What is the minimum amount of string she needs to buy?
Mathematics
2 answers:
MissTica3 years ago
7 0
How big is each bracelet?
MariettaO [177]3 years ago
6 0

Answer:

243 inches

Step-by-step explanation:

27 bracelets at 9inches each

9x27=243 inches or 20 feet and 1/4 inches of string. Depending on how the string is sold (by the foot, by the inch, yard, etc) will determine her minimum quantity, if you want to get specific.

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PLEASE ANSWER !
ivanzaharov [21]

Answer:I think no, because 25+35+45=150. 150x3=450

Maybe, for 4 months he'd have enough. So, 150x4=600. So Jamal would have some extra money!

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP! DUE SOON!!!!
yKpoI14uk [10]

Answer: yes

Step-by-step explanation:

4 0
2 years ago
Can someone help with this question
Zielflug [23.3K]

Answer:

<1= 60

<2=120

<3=60

<4=60

<5=120

<6=120

<7=60

Step-by-step explanation:

6 0
2 years ago
What fraction is equal to 65%?
umka21 [38]

Answer:

65/100

Divide is by 100.

4 0
3 years ago
A woman is randomly selected from the 18–24 age group. For women of this group, systolic blood pressures (in mm Hg) are normally
Naddik [55]

Answer:

X \sim N(114.8,13.1)  

Where \mu=114.8 and \sigma=13.1

We are interested on this probability

P(X>140)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

And we can find this probability using the complement rule:

P(z>1.924)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(114.8,13.1)  

Where \mu=114.8 and \sigma=13.1

We are interested on this probability

P(X>140)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:P(X>140)=P(\frac{X-\mu}{\sigma}>\frac{140-\mu}{\sigma})=P(Z>\frac{140- 1114.8}{2.6})=P(z>1.924)And we can find this probability using the complement rule:

P(z>1.924)=1-P(z

8 0
3 years ago
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