∠BDC=30, so ∠CBD + ∠BCD=180-30=150
ΔDBC is isosceles, so ∠CBD=∠BCD=half of 150=75
∠ABC=∠ABD-∠CBD=155-75=80
ΔABC is isosceles, so ∠ABC=∠ACB=80
∠BAC=180-80-80=20
We have to convert the measurements
the tray is 60 cm by 50 cm
if the cake tin is 25 cm in diameter, it will fit just 4 cakes because we have a length of 60 cm (will have 10 cm left over) and a width of 50 cm
hope it helps
Now,
(2x + y) (3x - 7)
2x (3x - 7y) + y (3x - 7)
6x^2 - 14xy + 3xy - 7y
6x^2 - 11xy - 7y
This is Right answer...
Answer:
The width of the frame is 2 inches
Step-by-step explanation:
The given dimensions of the picture = 7 inches by 7 inches
The area of the picture, A₁ = 7 in. × 7 in. = 49 in.²
The area of the given picture and the frame, A₂ = 81 square inches
Let 'w' represent the width of the frame and whereby the picture is a square, we have;
The area of the picture with the frame, A₂ = 81 in.² = (7 + w) × (7 + w)
A₂ = 81 = (7 + w) × (7 + w) = 49 + 14·w + w²
49 + 14·w + w² - 81 = 0
w² + 14·w - 32 = 0
(x + 16)·(x - 2) = 0
∴ x = -16 or x = 2
Given that 'x' is a natural number, we have;
The width of the frame, x = 2 inches.
