567 is the answer to your question
Answer:
Let's call the length of the field "l", and the width of the field "w".
If the area of the field is 72 square meters, then we have:
l x w = 72
And if the length is 6 meters longer than the width, we have:
l = w+6
So looking at the first equation (l x w = 72), we can substitute the l for a w+6.
And we obtain:
(w+6) x (w) = 72
Which simplifies to w^2 + 6w = 72.
This quadratic equation is pretty easy to solve, you just need to factor it.
w^2 + 6w - 72 = 0
(w-6)(w+12)
This leaves the roots of the quadratic equation to be 6 and -12, but in this case, a width of -12 wouldn't make sense.
So, the width of the rectangular field is 6, and the length of the field is 12.
Let me know if this helps!
B
Explanation sksnsnsnnsmams
Answer:
2/9 is the probability.
Step-by-step explanation:
Hope's this helps.
Answer:
34.01% probability that his score is at least 532.1.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

If 1 of the men is randomly selected, find the probability that his score is at least 532.1.
This is 1 subtracted by the pvalue of Z when X = 532.1. So



has a pvalue of 0.6591
1 - 0.6591 = 0.3409
34.01% probability that his score is at least 532.1.