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2 years ago

I need this question for unit test

Mathematics

1 answer:

krek1111 [17]2 years ago

3 0

The answer is this:
A. (6,3)

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Ayuda por fa es para hoy

kykrilka [37]

Translation: please help it's due today

Would love to help but there is no question to answer

7 0

1 year ago

PLEASE EXPLAIN TOO SO I CAN SOLVE OTHER SIMILAR ONES.

jeka57 [31]

Answer: x = 30' , y = 45'

hope this helps

Step-by-step explanation:

U is 90' it's a right triangle

well simple VRT you already know 2 angles which is 60' and 90'

R = 60'

V = 90'

T = x

you know that a triangle = 180'

so you do

180 - 60 - 90 = x

30 = x

if you want to do y

then you already know that U is 90' on both sides.

since you also know S,

S = 45'

U = 90'

V = y

180 - 90 - 45 = y

45 = y

4 0

2 years ago

What is the value of x ?

miv72 [106K]

the answer is 63 because 63*2=126 and 126+54=180 and all triangles add up to 180

7 0

2 years ago

Read 2 more answers

If the ratio of side lengths of similar polygons is 6:11, what is the ratio of perimeters?

Alchen [17]

6:11 because polygons have 4 side so it would be 24:44 but it just reduces back to 6:11. hope this helped have a good day!!

4 0

2 years ago

Please help me with this question

BartSMP [9]

Answer:

$3x-28=2x+25\\x=53$

Step-by-step explanation:

Parallel lines cut by a transversal are two lines which do not cross intersected by a third line. Because lines such as m and n are parallel, we have angles which are equal to each other.

Corresponding Angles - angles located in the same position in each intersection. Can be shown by translating or sliding the angle down/up.
Alternate Interior Angles - angles located inside the parallel lines across the transversal. Can be shown by reflecting and translating or rotation.
Alternate Exterior Angles - angles located outside the parallel lines across the transversal. Can be shown by reflecting and translating or rotation.

Vertical angles - angles across a vertex from one another. Can be shown by reflection.

The angles shown here are located outside the parallel lines and across the transversal from each other. Therefore we have Alternate Exteroir angles and can set them equal to each other to solve for x.

$3x-28=2x+25\\3x-2x-28=2x-2x+25\\x-28=25\\x-28+28=25+28\\x=53$

We check our work and should get equal angles:

$3(53)-28=2(53)+25\\159-28=106+25\\131=131$

4 0

2 years ago