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lutik1710 [3]
3 years ago
9

Which type of front is occurring at Point A on the map?

Chemistry
1 answer:
grin007 [14]3 years ago
5 0
Your answer would be A, a cold front

(Hope this is helpful)
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PLSSS HELP ANYONE ASAP!
algol [13]
B I hope it’s right I don’t really help a lot but yeah lol
7 0
3 years ago
Which base would not effectively deprotonate acetylene? (ch3)2nli ch3och2mgbr lioch3 ch3li kh?
Eva8 [605]

Acetylene has a chemical formula which can be written as:

C2H2

 

We can see that there are two positive ions, H+. Now what deprotonation means is that the H+ is removed from acetylene to form acetylene ion and water. In this case, I believe that the answer would be:

<span>LiOCH3</span>

8 0
3 years ago
Read 2 more answers
What volume (in L) of carbon dioxide will be produced from the reaction of 37.4 L of oxygen?
Anna [14]

Answer:

21.4 L

Explanation:

Given data:

Volume of carbon dioxide produced = ?

Volume of oxygen  = 37.4 L

Solution:

Chemical equation:

2C₂H₆ + 7O₂  →  4CO₂ + 6H₂O

It is known that,

1 mole = 22.414 L

There are 7 moles of oxygen = 7×22.414 = 156.9 L

There are 4 moles of carbon dioxide = 4×22.414 = 89.66 L

Now we will compare:

                              O₂             :              CO₂    

                              156.9         :              89.66

                                37.4         :             89.66/156.9×37.4 = 21.4 L

So from 37.4 L of oxygen 21.4 L of carbon dioxide is produced.

3 0
3 years ago
A client who weighs 70 kg is receiving a solution of 0.9% sodium chloride (normal saline) 500 ml with dopamine 800 mg at 5 ml/ho
nordsb [41]

The mcg/kg/minute the client is receiving is 1.904 mcg/kg/min whose weight is 70 kg.

<h3>What does mcg kg mean?</h3>

1 milligram (mg) = 1000 micrograms (mcg) or 0.001 grams (g) 1 g = 1000 mg 1 kilogram (kg) = 1000 g 1 kg = 2.2 pound (lb) 1 liter (L) = 1000 milliliters (mL)

The number of mcg/kg/minute = flow rate × concentration ÷ mass of client

Flow rate = 12 ml/hour = 12 ml/hour × 1 hr/60 min = 0.2 ml/min

Concentration = mass of dopamine/volume

where

mass of dopamine = 800 mg and

volume =  500 ml

Concentration =800 mg/500 ml

= 1.6 mg/ml

= 1.6 mg/ml × 1000 mcg/mg

= 1600 mcg/ml

mass of client = 70 kg

Calculating mcg/kg/minute

So, substituting the variables into the equation, we have

mcg/kg/minute = flow rate × concentration ÷ mass of client

mcg/kg/minute = 0.08 ml/min × 1600 mcg/ml ÷ 70 kg

mcg/kg/minute = 320 mcg/min ÷ 70 kg

mcg/kg/minute = 1.904 mcg/kg/min

Thus, the mcg/kg/minute the client is receiving is 1.904 mcg/kg/min

Learn more about mcg/kg/minute here:

brainly.com/question/4253005

#SPJ1

7 0
2 years ago
Calculate the solubility (in m) of cobalt(ii) hydroxide, co(oh)2(s) in h2o. ksp = 1.00×10-16 at a specific temperature.
antoniya [11.8K]
according to this reaction:

by using the ICE table:

              CO(OH)2 → CO2+  +  2OH-

intial                                0             0

change                           +X           +2X

Equ                                   X              2X

when Ksp = [CO2][OH-]^2

by substitution:

3.6 x 10^-16 = X * (2X)^2

3.6 x 10^-16 = 4 X^3

∴X = 3.88 x 10^-6 M
8 0
4 years ago
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