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liberstina [14]
3 years ago
13

An archeologist finds a 1.62 kg goblet that she believes to be made of pure gold. She determines that the volume of the goblet i

s 205 mL. Calculate the density of the goblet. I was wondering if it is 1.62/205? It is saying it it incorrect though!
Chemistry
1 answer:
katovenus [111]3 years ago
5 0
The  answer is

<span>The density (D) is quotient of mass (m) and volume (V):
</span>D= \frac{m}{V}
The unit is g/cm³

It is given:
m = 1.62 kg = 1620 g
V = 205 mL = 205 cm³
D = ?

Thus:
D= \frac{m}{V} = \frac{1620g}{205cm ^{3} } = 7.90 g/cm ^{3}

The density of the goblet is 7.90 g/cm³.
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A salt contains only magnesium and one of the halide ions. A 0.0776-g sample of the salt was dissolved in water, and an excess o
sdas [7]

Answer:

The formula of the magnesium halide is MgF₂

Explanation:

All halides, X, produce a salt with Mg with the formula:

MgX₂

<em>-There are 2 moles of the halide ion per mole of Mg-</em>

<em />

With the mass of the MgSO₄ we can find moles of magnesium sulfate  = Moles Mg.

With moles of Mg we can know the moles of the halide -1 mole Mg = 2 moles of Halide-

And we can find the mass of Mg in the 0.0776g sample. Subtracting we can find the mass of the halide and, with the mass and moles of the halide we can find its molecular weight and its identity:

<em>Moles MgSO₄ -Molar mass: 120.366g/mol- = Moles Mg:</em>

0.150g * (1mol / 120.366g) = 1.2462x10⁻³ moles Mg

<em>Moles halide:</em>

1.2462x10⁻³ moles Mg * 2 = <em>2.4924x10⁻³ moles Halide</em>

<em>Mass Mg -Molar mass: 24.305g/mol:</em>

1.2462x10⁻³ moles Mg * (24.305g / mol) = 0.0303g Mg

<em>Mass halide:</em>

0.0776g - 0.0303g Mg = <em>0.0473g</em>

<em>Molecular weight of the halide:</em>

0.0473g / 2.4924x10⁻³ moles =

18.98g/mol

This molecular weight is the molecular weight of Fluoride ion, F⁻,

<h3>The formula of the magnesium halide is MgF₂</h3>
6 0
3 years ago
What is the total number of electrons shown in this Lewis structure of carbon dioxide? A. 8 B. 12 C. 16 D. 24
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Answer is 16
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12 + 4 = 16
so carbon dioxide have 16 electron
8 0
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How many grams of NaOH are contained in 500 mL of a 0.80 M sodium hydroxide solution?
4vir4ik [10]

This is molarity: moles of solute/liters of solution. (Not molality)

1. Plug in what we know:

500 mL = 0.5 L

0.80 = moles/0.5

0.80*0.5 = moles

moles = 0.4

2. NaOH is given as 40 g/mole, so calculate the grams:

0.4 * 40 = 16 grams

answer: 16 grams

7 0
2 years ago
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