1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liberstina [14]
3 years ago
13

An archeologist finds a 1.62 kg goblet that she believes to be made of pure gold. She determines that the volume of the goblet i

s 205 mL. Calculate the density of the goblet. I was wondering if it is 1.62/205? It is saying it it incorrect though!
Chemistry
1 answer:
katovenus [111]3 years ago
5 0
The  answer is

<span>The density (D) is quotient of mass (m) and volume (V):
</span>D= \frac{m}{V}
The unit is g/cm³

It is given:
m = 1.62 kg = 1620 g
V = 205 mL = 205 cm³
D = ?

Thus:
D= \frac{m}{V} = \frac{1620g}{205cm ^{3} } = 7.90 g/cm ^{3}

The density of the goblet is 7.90 g/cm³.
You might be interested in
Suppose a group of volunteers is planning to build a park near a local lake. The lake is known to contain low levels of arsenic
ale4655 [162]

A) 10.75 is the concentration of arsenic in the sample in parts per billion .

B) 7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

C)It will take 1.37 years to remove all of the arsenic from the lake.

Explanation:

A) Mass of arsenic in lake water sample = 164.5 ng

The ppb is the amount of solute (in micrograms) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

\text{ppb}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^9

Both the masses are in grams.

We are given:

Mass of arsenic = 164.5 ng = 164.5\times 10^{-9} g

1 ng=10^{-9} g

Volume of the sample = V = 15.3 cm^3

Density of the lake water sample ,d= 1.00 g/cm^3

Mass of sample =  M = d\times V=1.0 g/cm^3\times 15.3 cm^3=15.3 g

ppb=\frac{164.5\times 10^{-9} g}{15.3 g}\times 10^9=10.75

10.75 is the concentration of arsenic in the sample in parts per billion.

B)

Mass of arsenic in 1 cm^3  of lake water = \frac{164.5\times 10^{-9} g}{15.3}=1.075\times 10^{-8} g

Mass of arsenic in 0.710 km^3 lake water be m.

1 km^3=10^{15} cm^3

Mass of arsenic in 0.710\times 10^{15} cm^3 lake water :

m=0.710\times 10^{15}\times 1.075\times 10^{-8} g=7,633,660.130 g

1 g = 0.001 kg

7,633,660.130 g = 7,633,660.130 × 0.001 kg=7,633.660130 kg ≈ 7,633.66 kg

7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

C)

Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.

Days required to remove 1 kilogram of arsenic from the lake water :

\frac{2.74}{41.90} days

Then days required to remove 7,633.66 kg of arsenic from the lake water :

=7,633.66\times \frac{2.74}{41.90} days=499.19 days

1 year = 365 days

499.19 days = \frac{499.19}{365} years = 1.367 years\approx 1.37 years

C)

Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.

Days required to remove 1 kilogram of arsenic from the lake water :

\frac{2.74}{41.90} days

Then days required to remove 7,633.66 kg of arsenic from the lake water :

=7,633.66\times \frac{2.74}{41.90} days=499.19 days

1 year = 365 days

499.19 days = \frac{499.19}{365} years = 1.367 years\approx 1.37 years

It will take 1.37 years to remove all of the arsenic from the lake.

6 0
3 years ago
What is the result of adding 2.5 × 10³ and 3.5 × 10²?
Elanso [62]

Answer:

A

Explanation:

It is correct please I hope it helps! :)

7 0
3 years ago
Read 2 more answers
Help me please im in 4th grade and online is frustrating
Snowcat [4.5K]

Answer:

A

Explanation:

The answer is A) because the A container has tightly packed molecules but not as tight as C so that means A is liquid, and C is a solid which makes B a gas

7 0
3 years ago
Balancing equations<br> I'll give brainliest.
wel

Answer:

You should follow these steps:

Count each type of atom in reactants and products.

Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances.

Repeat steps 1 and 2 until the equation is balanced.

Explanation:

7 0
2 years ago
In the combustion chamber of an engine, the initial volume is 450 cm3 at a pressure of 1.0 atmosphere. If the piston displaces 4
Alona [7]

Assuming that the contents of the chamber ar ideal gases. We can use the relation PV=nRT.  At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

P2 = (1)(450)/ 48

P2 = 9.375 atm

3 0
3 years ago
Other questions:
  • Compare and contrast the fine and coarse adjustment knobs on a microscope
    15·1 answer
  • What properties of matter explain why the weight of an object on the moon is different than the weight of the same object on ear
    8·1 answer
  • An animal skeleton has a carbon-14 decay rate of 13.1 disintegrations per minute per gram of carbon. When did the animal die? (A
    13·1 answer
  • Molecules inside a liquid _____.
    7·2 answers
  • What is the chemical formula for the compound ammonium phosphate?
    7·1 answer
  • What is the molar solubility of calcium carbonate ( CaCO3 ) in water? The solubility-product constant for CaCO3 is 4.5 × 10-9 at
    8·1 answer
  • Which wave has the longest wavelength ?Shortest?
    10·2 answers
  • I REALLY NEED HELP WITH THIS: The ball has a mass of 2 kg and a final speed of 5 m/s. What is the kinetic energy of the ball? Gi
    7·1 answer
  • PLS HELP AND NO LINKS PLS<br> What place is affected by acid rain and why?
    14·1 answer
  • Help me please:(:(:( with my bellwork<br> for brainiest
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!