Complete question is;
A pure copper penny contains approximately 2.9 × 10^(22) copper atoms.
1 doz = 12
1 gross = 144
1 ream = 500
1 mol = 6.022 × 10^(23)
Use these definitions to determine the following:
A) How many dozens of copper atoms are in a penny.
B) How many gross of copper atoms are in a penny
C) How many reams of copper atoms are in a penny.
D) how many moles of copper atoms are in a penny?
All answers can be rounded to two significant figures
Answer:
A) 2.4 × 10^(21) dozens
B) 2.01 × 10^(20) gross
C) 5.8 × 10^(19) reams
D) 0.048 mol
Explanation:
A) A dozen contains 12.
Therefore, 2.9 × 10^(22) copper atoms will contain;
(2.9 × 10^(22))/12 dozens = 2.42 × 10^(21).
In 2 significant figures, we have;
2.4 × 10^(21) dozens
B) 1 gross = 144
Therefore, 2.9 × 10^(22) copper atoms will contain;
(2.9 × 10^(22))/144 gross ≈ 2.01 × 10^(20) gross
C) 1 ream = 500
Therefore, 2.9 × 10^(22) copper atoms will contain;
(2.9 × 10^(22))/500 reams = 5.8 × 10^(19) reams
D) 1 mol = 6.022 × 10^(23)
Therefore, 2.9 × 10^(22) copper atoms will contain;
(2.9 × 10^(22))/(6.022 × 10^(23)) = 0.048 mol
