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Veronika [31]
2 years ago
10

The length of a rectangular frame is 15 inches , and the width of the frame is 8 inches . What is the length of a diagonal of th

is frame in inches ?
Mathematics
1 answer:
sp2606 [1]2 years ago
6 0

Answer:

Step-by-step explanation:

d=17in

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The diagram shows a square of side 3 in. containing a circle of diameter 3 in. To the nearest hundredth, what is the area of the
Westkost [7]
The area of the square is 9 square inches.
The area of the circle is about 7.065. As a result, the area of the shading region is 1.94 square inches. Hope it help!
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3 years ago
Ill make you brainliest answer!!
galina1969 [7]
I think using a computer software would be the best answer because it is then fair
3 0
3 years ago
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Cleo wants to jion a gym. There is an initiation fee of $24.99, and each month of membership costs $12.50. If Cleo pays $174.99,
mamaluj [8]

Answer: The membership will last for 12 months.

Step-by-step explanation:

Let x represent the number of months that the membership would last.

Cleo wants to join a gym. There is an initiation fee of $24.99, and each month of membership costs $12.50. This means that the total cost of using the gym for x months would be expressed as

12.5x + 24.99

If Cleo pays $174.99, it means that

12.5x + 24.99 = 174.99

12.5x = 174.99 - 24.99

12.5x = 150

x = 150/12.5

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6 0
3 years ago
plz help quick. the sum of two numbers is 11. Three times the first number minus the second number is -3. what are the numbers?
Lerok [7]

Answer:

the first number is 2, the second number is 9 :)

Step-by-step explanation:

brainliest? :)

6 0
3 years ago
Solve this for Brainliest!<br><br>See the attachment [Level - GCSE]
madreJ [45]

Answer:

x = 3 + 4\sqrt{3}

Step-by-step explanation:

OPQ is a right angle triangle.

<u>Using Pythagoras</u>

x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0

<u>Using quadratic formula</u>

<u />x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}

x = 3 + 4\sqrt{3} = 9.928(4s.f.)

             OR

x = 3 - 4\sqrt{3} = -3.928(4s.f.) (Length can't be negative)

∴ x = 3 + 4\sqrt{3}

3 0
2 years ago
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