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3 years ago

10

The length of a rectangular frame is 15 inches , and the width of the frame is 8 inches . What is the length of a diagonal of th

is frame in inches ?

1 answer:

sp2606 [1]3 years ago

6 0

Answer:

Step-by-step explanation:

d=17in

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Eric wants to attend a public four-year university. He estimates that the average cost of one year at this university is $19,500

rjkz [21]

325 * 60 = 19500 so 60 months

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3 years ago

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If f'(x) = 12x^3 - 2x^2 - 17 and f(1) = 8 , find f(x).

Cloud [144]

Answer:

f(x) = 3x⁴ - $\frac{2X^{3} }{3}$ - 17x + $\frac{68}{3}$

Step-by-step explanation:

To find f'(x), we will follow the steps below:

We will start by integrating both-side of the equation

∫f'(x) = ∫(12x^3 - 2x^2 - 17)dx

f(x) = 3x⁴ - $\frac{2X^{3} }{3}$ - 17x + C

Then we go ahead and find C

f(1) = 8

so we will replace x by 1 in the above equation and solve for c

f(1) = 3(1)⁴ - $\frac{2(1)^{3} }{3}$ - 17(1) + C

8 = 3 - $\frac{2}{3}$ - 17 + C

C =8 - 3 + 17 + $\frac{2}{3}$

C = 22 + $\frac{2}{3}$

C = $\frac{66 + 2}{3}$

C = $\frac{68}{3}$

f(x) = 3x⁴ - $\frac{2X^{3} }{3}$ - 17x + $\frac{68}{3}$

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4 years ago

Write the equation of a parabola with a vertex and (-5, 2) and a directrix y = -1

mrs_skeptik [129]

Answer:

y=(x+5)²/6 + 1/3

Step-by-step explanation:

Use the distance formula to plug in the values you know:

√(y+1)² =√(x+5)² +( y-2)²

the square roots cancel out

(y+1) ²= (x+5)² +(y-2)²

(y+1) (y-1)= (x+5)² + (y-2) (y-2)

y²+2y+1= (x+5)² + y² -4y+4

the y² cancel out

2y+ 4y = (x+5)² + 4-1

6y= (x+5)² +3

y= (x+5)² /6+ 1/3

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3 years ago

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Musya8 [376]

Answer:B

Step-by-step explanation:

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