The Formula of Acetone is

To find the Mass Molar of a compound, you add the Atomic weights of it's atoms.
If you check the Periodic table:
Atomic Weight of Carbone C: 12.0107
Atomic Weight of Hydrogen: 1.00794
Atomic Weight of Oxygen: 15.9994
So, you got:
Total Atomic Weight of Carbone in Acetone: 12.0107 * 3 = 36.0321
Total Atomic Weight of Hydrogen in Acetone: 1.00794 * 6 = 6.04764
Total Atomic Weight of Oxygen in Acetone = 15.9994 * 1 = 15.9994
Now, you add this numbers
36.0321 + 6.04764 + 15.9994 = 58.07914
So, the Molar Mass of Acetone is 58.09714 g/mol
Hope this Helps :D
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Answer:
1}800m/s
2}80m/s²
Explanation:
1]first convert the kilometers to meters so as to obtain similar units;
16×1000=16000m (1Km=1000m)
then divide the ditance by time:
speed=distance/time
=16000m/2s
=800m/s
2]acceleration=(initial velocity -final velocity)/time taken
=(800m/s-0m/s)/10s
=800m/s/10s
=80m/s²
Answer:
pH = 3.513
Explanation:
Hello there!
In this case, since this titration is carried out via the following neutralization reaction:

We can see the 1:1 mole ratio of the acid to the base and also to the resulting acidic salt as it comes from the strong HCl and the weak hydroxylamine. Thus, we first compute the required volume of HCl as shown below:

Now, we can see that the moles of acid, base and acidic salt are all:

And therefore the concentration of the salt at the equivalence point is:
![[HONH_3^+Cl^-]=\frac{0.0044mol}{0.022L+0.0293L} =0.0858M](https://tex.z-dn.net/?f=%5BHONH_3%5E%2BCl%5E-%5D%3D%5Cfrac%7B0.0044mol%7D%7B0.022L%2B0.0293L%7D%20%3D0.0858M)
Next, for the calculation of the pH, we need to write the ionization of the weak part of the salt as it is able to form some hydroxylamine as it is the weak base:

Whereas the equilibrium expression is:
![Ka=\frac{[H_3O^+][HONH_2]}{[HONH_3^+]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BHONH_2%5D%7D%7B%5BHONH_3%5E%2B%5D%7D)
Whereas Ka is computed by considering Kw and Kb of hydroxylamine:

So we can write:

And neglect the x on bottom to obtain:

And since x=[H3O+] we obtain the following pH:

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