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dedylja [7]
3 years ago
8

Use the scenario to answer the question

Chemistry
2 answers:
guajiro [1.7K]3 years ago
9 0

Answer: here’s your answer You are visiting your Grandmother and notice that she is eating a balanced diet, taking vitamins, getting the proper amount of sleep and is not overweight. Despite her healthy lifestyle, she appears run down and tired. You realize that it's due to her lack of physical activity. Write a convincing letter to your grandma explaining the benefits of participating in regular physical activity.

You are visiting your Grandmother and notice that she is eating a balanced diet, taking vitamins, getting the proper amount of sleep and is not overweight. Despite her healthy lifestyle, she appears run down and tired. You realize that it's due to her lack of physical activity. Write a convincing letter to your grandma explaining the benefits of participating in regular physical activity.

You are visiting your Grandmother and notice that she is eating a balanced diet, taking vitamins, getting the proper amount of sleep and is not overweight. Despite her healthy lifestyle, she appears run down and tired. You realize that it's due to her lack of physical activity. Write a convincing letter to your grandma explaining the benefits of participating in regular physical activity.

You are visiting your Grandmother and notice that she is eating a balanced diet, taking vitamins, getting the proper amount of sleep and is not overweight. Despite her healthy lifestyle, she appears run down and tired. You realize that it's due to her lack of physical activity. Write a convincing letter to your grandma explaining the benefits of participating in regular physical activity.

Explanation:

Vinil7 [7]3 years ago
6 0

wjwhhw

Answer:

jeheheb

Explanation:

nsbsjeenbeebebbeesbbebe

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A student determines the molar mass of acetone
love history [14]
The Formula of Acetone is C_3H_6O
To find the Mass Molar of a compound, you add the Atomic weights of it's atoms.
If you check the Periodic table:
Atomic Weight of Carbone C: 12.0107
Atomic Weight of Hydrogen: 1.00794
Atomic Weight of Oxygen: 15.9994 

So, you got:
Total Atomic Weight of Carbone in Acetone: 12.0107 * 3 = 36.0321 
Total Atomic Weight of Hydrogen in Acetone: 1.00794 * 6 = 6.04764
Total Atomic Weight of Oxygen in Acetone = 15.9994 * 1 = 15.9994

Now, you add this numbers
36.0321 + 6.04764 + 15.9994 = 58.07914

So, the Molar Mass of Acetone is 58.09714 g/mol

Hope this Helps :D
7 0
3 years ago
What did the 15th amendment do
Alisiya [41]

The 15th Amendment to the Constitution granted African American men the right to vote by declaring that the "right of citizens of the United States to vote shall not be denied or abridged by the United States or by any state on account of race, color, or previous condition of servitude."

6 0
4 years ago
1.Calculate the end velocity of a rocket that traveled 16km in 2 seconds.
fomenos

Answer:

1}800m/s

2}80m/s²

Explanation:

1]first convert the kilometers to meters so as to obtain similar units;

16×1000=16000m   (1Km=1000m)

then divide the ditance by time:

speed=distance/time  

=16000m/2s

=800m/s

2]acceleration=(initial velocity -final velocity)/time taken

=(800m/s-0m/s)/10s

=800m/s/10s

=80m/s²

8 0
4 years ago
Which is NOT needed to START a wildfire.
ratelena [41]

Answer:

you are correct

Explanation:

6 0
3 years ago
Read 2 more answers
Calculate the pH at the equivalence point when 22.0 mL of 0.200 M hydroxylamine, HONH2, is titrated with 0.15 M HCl. (Kb for HON
solniwko [45]

Answer:

pH = 3.513

Explanation:

Hello there!

In this case, since this titration is carried out via the following neutralization reaction:

HONH_2+HCl\rightarrow HONH_3^+Cl^-

We can see the 1:1 mole ratio of the acid to the base and also to the resulting acidic salt as it comes from the strong HCl and the weak hydroxylamine. Thus, we first compute the required volume of HCl as shown below:

V_{HCl}=\frac{22.0mL*0.200M}{0.15M}=29.3mL

Now, we can see that the moles of acid, base and acidic salt are all:

0.0220L*0.200mol/L=0.0044mol

And therefore the concentration of the salt at the equivalence point is:

[HONH_3^+Cl^-]=\frac{0.0044mol}{0.022L+0.0293L} =0.0858M

Next, for the calculation of the pH, we need to write the ionization of the weak part of the salt as it is able to form some hydroxylamine as it is the weak base:

HONH_3^++H_2O\rightleftharpoons H_3O^++HONH_2

Whereas the equilibrium expression is:

Ka=\frac{[H_3O^+][HONH_2]}{[HONH_3^+]}

Whereas Ka is computed by considering Kw and Kb of hydroxylamine:

Ka=\frac{Kw}{Kb}=\frac{1x10^{-14}}{9.10x10^{-9}}  \\\\Ka=1.10x10^{-6}

So we can write:

1.10x10^{-6}=\frac{x^2}{0.0858-x}

And neglect the x on bottom to obtain:

1.10x10^{-6}=\frac{x^2}{0.0858}\\\\x=\sqrt{1.10x10^{-6}*0.0858}=3.07x10^{-4}M

And since x=[H3O+] we obtain the following pH:

pH=-log(3.07x10^{-4})\\\\pH=3.513

Regards!

4 0
3 years ago
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