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Sergeu [11.5K]
3 years ago
13

A student obtains a mixture of the chlorides of two unknown metals, X and Z. The percent by mass of X and the percent by mass of

Z in the mixture is known. Which of the following additional information is most helpful in calculating the mole percent of XCl(s) and of ZCl(s) in the mixture?
Chemistry
2 answers:
Hitman42 [59]3 years ago
6 0

Answer:

Molar masses of X and Z

Explanation:

To determine the mole percent of a mixture ( mole percent of unknown metals = number of mole of each of them divided the total of both the unknown salt × 100) since the percent by mass is know; we the molar mass of X and  Z

mole = mass given / molar mass

g100num [7]3 years ago
6 0

Answer:

the Molar masses of Z and X

Explanation:

The percent by mass of X states how many grams of X are in 100 grams of the mixture. Then, we know how many grams of X, Z (we also know its percent) and of Cl ( = 100 - X % - Z %). Taking 100 g of the mixture as a base, we have:

x grams of X

z grams of Z

y grams of Cl

With the molar masses of Z and X (and of Cl) we can transform all masses into moles and then compute the mole percent of XCl(s) and of ZCl(s) in the mixture

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A 35.6 mL solution of Sr(OH)2 is titrated with 0.549 L of 0.0445 M HBr. Determine the concentration of strontium hydroxide.
ozzi

Answer:

The answer to your question is  0.34 M  

Explanation:

Data

[Sr(OH)₂] = ?

Volume of Sr(OH)₂ = 35.6 ml or 0.0356 l

[HBr] = 0.0445 M

Volume of HBr = 0.549 l

Balanced chemical reaction

                 2HBr  +  Sr(OH)₂  ⇒  SrBr₂   +   2H₂O

Process

1.- Calculate the moles of HBr

Molarity = moles / volume

-Solve for moles

moles = Molarity x volume

-Substitution

moles = 0.0445 x 0.549

          = 0.0244

2.- Calculate the moles of Sr(OH)₂ using the coefficients of the balanced reaction

                    2 moles of HBr ----------------------- 1 mol of Sr(OH)₂

                    0.0244 moles   -----------------------  x

                                   x = (0.0244 x 1) / 2

                                   x = 0.0122 moles of Sr(OH)₂

3.- Calculate the concentration of Sr(OH)₂

Molarity = 0.0122/ 0.0356

-Simplification

Molarity = 0.34                      

5 0
3 years ago
The rate law for the reaction NH4(aq)+ + NO2(aq)- → H2O(l) + NO2(g) is rate = k [NH4+][NO2-], and the value of k is 2.7*10-4 M-1
dybincka [34]
We are given the rate law, so we can substitute the given values for the rate constant and the concentrations of the reactants to solve for the rate of reaction. Since rate = k [NH4+][NO2-]:
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8 0
3 years ago
Read 2 more answers
A scientist measures the standard enthalpy change for the following reaction to be 67.9 kJ:
hodyreva [135]

Answer:

-252.5 kJ/mol = ΔH H2O(g)

Explanation:

ΔH Fe2O3 = -825.5kJ/mol

ΔH H2 = 0kJ/mol

ΔH Fe = 0kJ/mol

Based on Hess's law, ΔH of a reaction is the sum of ΔH of products - ΔH of reactants. For the reaction:

Fe2O3(s) + 3 H2(g) →2Fe(s) + 3 H2O(g)

ΔHr = 67.9kJ/mol = 3*ΔH H2O + 2*ΔHFe - (ΔH Fe2O3 + 3*Δ H2)

67.9kJ/mol = 3*ΔH H2O + 2*0kJ/mol - (ΔH -825.5kJ/mol + 3*Δ H2)

67.9 = 3*ΔH H2O(g) + 825.5kJ/mol

-757.6kJ/mol = 3*ΔH H2O(g)

<h3>-252.5 kJ/mol = ΔH H2O(g)</h3>
6 0
3 years ago
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